Skip to main content

evaluation - Simplifying expression with non-commutating entries


Say I have an expression such as


(a + X)**(b-Y)


where the variables above possess the following commutation relations [a, b] = [a, X] = [a, Y] = [b, X] = [b, Y] = 0 and [X, Y] is nonzero.


I want to use mathematica to expand out these terms. This can be done using the "Distribute" command. The input is


Distribute[(a + X)**(b-Y)]

and the output is


a ** b + a ** (-Y) + X ** b + X ** (-Y).

I now want to simplify this expression using the commutation relations given above. I'm not sure how to go about uploading these commutation relations into mathematica such that this expression can be simplified.



Answer




One way to achieve what is asked in the question, is to introduce an identity id which commutes with all quantities but can be used together with X and Y to efficiently tell NonCommutativeMultiply how to treat scalars a, b, and c:


Clear[id]
id /: NonCommutativeMultiply[id, y_] := y
id /: NonCommutativeMultiply[x_, id] := x

Unprotect[NonCommutativeMultiply];
NonCommutativeMultiply[x___, HoldPattern[Times[id, a_]],
y___] := a NonCommutativeMultiply[x, id, y]
NonCommutativeMultiply[x___, HoldPattern[Times[X, a_]],
y___] := a NonCommutativeMultiply[x, X, y]

NonCommutativeMultiply[x___, HoldPattern[Times[Y, a_]],
y___] := a NonCommutativeMultiply[x, Y, y]
Protect[NonCommutativeMultiply];

In defining the properties of NonCommutativeMultiply, I had to temporarily use UnProtect. The purpose of id is seen in the three last lines: I can now define the linearity of ** under regular multiplication by a scalar a in the same way for the elements id, X and Y. But by specifying that id commutes with X and Y, I designate it as the element that accompanies all scalars a: instead of writing a for a commuting element, you therefore have to write a id.


The benefit of this additional convention is that I don't need to add specific definitions for each individual variable name that is intended to be a scalar. Anything that appears in the form a id or id c etc. is a scalar by definition.


Here is what the example looks like:


Distribute[(a id + X) ** (b id - Y)]

(* ==> a b id + b X - a Y - X ** Y *)


In the result, id again appears in the one term that has only scalars in it.


To make the definitions even shorter, you could replace all three lines between Unprotect and Protect by this:


NonCommutativeMultiply[x___,HoldPattern[Times[p:(id|X|Y),a_]],y___]:=
a NonCommutativeMultiply[x,p,y]

Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...