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plotting - How can I create a rectangular graphic with curved edges?


I want to make some button shaped graphics that would essentially be a rectangular shape with curved edges. In the example below I have used Polygon rather than Rectangle so as to take advantage of VertexColors and have a gradient fill. The code below illustrates the sort of thing I want in so far as the Frame with RoundingRadius shows where I want the boundaries of the Graphic to be cut off (for example).


Framed[Graphics[{

   Polygon[{{0, 0}, {1, 0}, {1, 1}, {0, 1}}, 
    VertexColors -> {Red, Red, Blue, Blue}]
   },
  AspectRatio -> 0.2,
  ImagePadding -> 0,
  ImageMargins -> 0,
  ImageSize -> 200,
  PlotRangePadding -> 0],
 ContentPadding -> True,
 FrameMargins -> 0,

 ImageMargins -> 0,
 RoundingRadius -> 20]

I'm thinking there is probably a very straight forward way of accomplishing this. Is there some way to exclude parts of the Graphic that fall outside the Frame from displaying? Any alternative methods would be welcome.


Edit


I had been expecting that this was going to be possible with existing options rather than having to write functions. @Mr.Wizard provided a concise solution from existing built in functionality but I ultimately didn't want a raster solution. @Heike used RegionPlot like the others, but in a way in which the user, i.e. me, could implement it by simply changing a rounding radius parameter, so that makes it a more straight forward solution IMO.



Answer



This answer uses RegionPlot to plot the rounded rectangle. In roundedRect, {{xmin, xmax}, {ymin, ymax}} is the range of the rectangle and rad the rounding radius. roundedRect accepts any option of RegionPlot, in particular ColorFunction which you can use to shade the rectangle.


Options[roundedRect] = Options[RegionPlot];
SetOptions[roundedRect, {Frame -> False, Axes -> False, BoundaryStyle -> None}];


roundedRect[range : {{xmin_, xmax_}, {ymin_, ymax_}}, rad_, 
  opt : OptionsPattern[roundedRect]] := Module[{p, norm},
  p = 1/Log2[Sqrt[2] + 2];
  norm[pt_, pt0_] := Total[Abs[pt - pt0]^p]^(1/p) > rad;
  RegionPlot[And @@ (norm[{x, y}, #] & /@ Tuples[range]),
   {x, xmin, xmax}, {y, ymin, ymax}, opt,
   AspectRatio -> Abs[ymax - ymin]/Abs[xmax - xmin],
   Evaluate[Options[roundedRect]]]]


Example


roundedRect[{{0, 5}, {0, 1}}, .4, ColorFunction -> (Blend[{Red, Blue}, #2] &)]

Mathematica graphics


Edit


@Heike I hope you do not mind me making a change to your answer. I think this is more Mathematica like by having the rounding radius as an option.


ClearAll[roundedRect];

Options[roundedRect] = Flatten[{RoundingRadius -> 0.5, Options[RegionPlot]}];
SetOptions[roundedRect, {Frame -> False, Axes -> False, BoundaryStyle -> None}];


roundedRect[range : {{xmin_, xmax_}, {ymin_, ymax_}}, 
  opt : OptionsPattern[roundedRect]] := Module[{p, norm, opts, rad},

  rad = OptionValue[RoundingRadius];
  opts = FilterRules[{opt}, Options[RegionPlot]];

  p = 1/Log2[Sqrt[2] + 2];
  norm[pt_, pt0_] := Total[Abs[pt - pt0]^p]^(1/p) > rad;


  RegionPlot[
   And @@ (norm[{x, y}, #] & /@ Tuples[range]), {x, xmin, xmax}, {y, 
    ymin, ymax}, Evaluate@opts,
   AspectRatio -> Abs[ymax - ymin]/Abs[xmax - xmin]]]

example:


roundedRect[{{0, 5}, {0, 1}}, Frame -> False, RoundingRadius -> 0.4, 
 ColorFunction -> (Blend[{Red, Blue}, #2] &)]

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