Skip to main content

plotting - Help remove annoying vertical lines in a piecewise plot


I use the following codes to define and plot three piecewise functions.


list1 = Join[
Table[{(j - 1)/2^1, (j - 1)/2^1 <= E^x < j/2^1}, {j, 1,
1*2^1}], {{1, E^x >= 1}}];
list2 = Join[
Table[{(j - 1)/2^2, (j - 1)/2^2 <= E^x < j/2^2}, {j, 1,

2*2^2}], {{2, E^x >= 2}}];
list3 = Join[
Table[{(j - 1)/2^3, (j - 1)/2^3 <= E^x < j/2^3}, {j, 1,
3*2^3}], {{3, E^x >= 3}}];
p1 = Piecewise[list1];
p2 = Piecewise[list2];
p3 = Piecewise[list3];

Plot[p1, {x, -3, 3}, AspectRatio -> Automatic]
Plot[p2, {x, -3, 3}, AspectRatio -> Automatic]

Plot[p3, {x, -3, 3}, AspectRatio -> Automatic]

p1 and p2 just come out fine, while p3 is messy, with end points of each horizontal lines connected by vertical lines.


Thank you!


enter image description here



Answer



Using @Rojo's answer to my question here you don't need to know a priori where the exclusions are:


plot = Plot[p3, {x, -3, 3}, PlotPoints -> 1000];

pp = With[{multiplier = {AspectRatio, PlotRange} /.

AbsoluteOptions[plot, {AspectRatio, PlotRange}] /. {ar_, pl_} :>
ar Divide @@ Subtract @@@ Reverse /@ pl},
(plot //.
Line[{a___, {x1_, y1_}, {x2_, y2_}, b___}] /;
Abs[(y1 - y2)/(x1 - x2)] > 10/multiplier :> {Line[{a, {x1, y1}}],
Line[{{x2, y2}, b}]})
];

Show[pp, AspectRatio -> Automatic]


Mathematica graphics


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...

list manipulation - Selecting multiple columns from a matrix?

Sample data: data = { {{2013, 1, 1}, 24.13, 167.67, 231.82}, {{2013, 1, 2}, 32.15, 170.92, 225.99}, {{2013, 1, 3}, 35.43, 172.68, 221.67}, {{2013, 1, 4}, 36.73, 173.05, 218.32}, {{2013, 1, 5}, 58.19, 165.96, 197.05}, {{2013, 1, 6}, 69.99, 163.50, 187.52}, {{2013, 1, 7}, 71.37, 154.21, 175.58}, {{2013, 1, 8}, 72.51, 149.66, 163.25}}; I want a DateListPlot with three graphs, so for a matrix formed by columns 1 and 2, one for columns 1 and 3, and 1 for columns 1 and 4. At the moment I'm using this code: data2 = Transpose[{data[[All, 1]], data[[All, 2]]}]; data3 = Transpose[{data[[All, 1]], data[[All, 3]]}]; data4 = Transpose[{data[[All, 1]], data[[All, 4]]}]; DateListPlot[{data2, data3, data4}, Joined -> True, Filling -> {3 -> {1}}] but I have a hunch that this can be done more efficiently. I don't like the Transpose s in particular. Any ideas? edit (for extra credit) What if I need to multiply the second column by 2, which in my solution is simp...