Skip to main content

graphics3d - How to Discretize a Tube


In Is there a way to outline text?, I was amazed that BoundaryDiscretizeGraphics can discretize a Text primitive. So in a similar way, I wanted to apply DiscretizeGraphics to a Tube like this:


DiscretizeGraphics @ Graphics3D[Tube[{{0, 0, 0}, {1, 1, 1}}, .1]]

or


tube = Tube[{{0, 0, 0}, {1, 1, 1}}, .1];
BoundaryDiscretizeGraphics[tube, #] & /@ {_Tube, _Polygon, _Line, _Point}


But I failed to do it. Is it a bug in Mathematica, or is it some mistake in my code?



Answer



It took quite a while, but I've finally come up with a way to generate discretized tubes. This again is based on work in this previous answer (from the thread mentioned earlier by Michael). In the interest of keeping things short, I will not be repeating the definitions of orthogonalDirections[], extend[], and crossSection[] from that answer. Here, then, is the tube generator:


makeCap[type : ("Butt" | "Round" | "Square"), s : (-1 | 1), path_?MatrixQ, tube_?ArrayQ,
r_?NumericQ, h_?NumericQ] :=
Module[{d = Take[path, 2 s], cs, p, t0, t1},
cs = tube[[s]];
t0 = h; t1 = 1 - h Boole[type =!= "Square"];
If[s == -1, {t0, t1} = {t1, t0}];
If[type === "Butt",

{d[[s]],
Table[ScalingTransform[{t, t, t}, d[[s]]] @ cs, {t, t0, t1, s h}]},
p = (s r/(EuclideanDistance @@ d)) ({1, -1}.d);
{d[[s]] + p, Switch[type,
"Round",
Table[Composition[TranslationTransform[p Cos[Ï€ t/2]],
ScalingTransform[{1, 1, 1} Sin[Ï€ t/2], d[[s]]]][cs],
{t, t0, t1, s h}],
"Square",
Table[Composition[TranslationTransform[p],

ScalingTransform[{t, t, t}, d[[s]]]][cs],
{t, t0, t1, s h}]]}]]

Options[TubeMesh] = {"CapForm" -> None, "CirclePoints" -> Automatic,
"MeshType" -> Automatic, Tolerance -> Automatic};

TubeMesh[path_?MatrixQ, r_?NumericQ, opts : OptionsPattern[{TubeMesh, MeshRegion}]] :=
Module[{c0, c1, cf, mt, dims, h, idx, m, n, p0, p1, t0, t1, tol, tube},
cf = OptionValue["CapForm"]; mt = OptionValue["MeshType"];
If[mt === Automatic,

mt = If[MatchQ[cf, "Butt" | "Round" | "Square"],
BoundaryMeshRegion, MeshRegion]];
tol = OptionValue[Tolerance] /. Automatic -> 0.0015;
n = OptionValue["CirclePoints"];
If[n === Automatic, n = Round[17 tol^(-1/3)/5 - 57 tol^(1/3)/59];
n += Boole[OddQ[n]]]; h = 2/n;
tube = FoldList[Function[{p, t},
extend[p, t[[2]], t[[2]] - t[[1]],
orthogonalDirections[t]]],
crossSection[path, r, n], Partition[path, 3, 1, {1, 2}, {}]];

If[MatchQ[cf, "Butt" | "Round" | "Square"],
{p0, c0} = makeCap[cf, 1, path, tube, r, h];
{p1, c1} = makeCap[cf, -1, path, tube, r, h];
tube = Join[c0, tube, c1]];
dims = Most[Dimensions[tube]]; tube = Apply[Join, tube];
m = Times @@ dims; idx = Partition[Range[m], Last[dims]]; t0 = t1 = {};
If[MatchQ[cf, "Butt" | "Round" | "Square"],
PrependTo[tube, p0]; AppendTo[tube, p1]; idx += 1;
t0 = PadLeft[Partition[First[idx], 2, 1], {Automatic, 3}, 1];
t1 = PadRight[Reverse /@ Partition[Last[idx], 2, 1],

{Automatic, 3}, m + 2]];
mt[tube, Triangle[Join[t0,
Flatten[Apply[{Append[Reverse[#1], Last[#2]],
Prepend[#2, First[#1]]} &,
Partition[idx, {2, 2}, {1, 1}], {2}], 2], t1]],
FilterRules[{opts}, Options[MeshRegion]]]]

As designed, TubeMesh[] will return a MeshRegion[] object for the setting "CapForm" -> None, and a BoundaryMeshRegion[] for the other "CapForm"s.


Using once more the example path in the previous answer:


path = First @ Cases[ParametricPlot3D[

BSplineFunction[{{0, 0, 0}, {1, 1, 1}, {2, -1, -1},
{3, 0, 1}, {4, 1, -1}}][u] // Evaluate, {u, 0, 1},
MaxRecursion -> 1], Line[l_] :> l, ∞];

TubeMesh[path, 1/5, "CapForm" -> "Round", PlotTheme -> "SmoothShading"]

some tube converted into a region


Compute the volume:


Volume[%]
0.727654081738915

Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...

list manipulation - Selecting multiple columns from a matrix?

Sample data: data = { {{2013, 1, 1}, 24.13, 167.67, 231.82}, {{2013, 1, 2}, 32.15, 170.92, 225.99}, {{2013, 1, 3}, 35.43, 172.68, 221.67}, {{2013, 1, 4}, 36.73, 173.05, 218.32}, {{2013, 1, 5}, 58.19, 165.96, 197.05}, {{2013, 1, 6}, 69.99, 163.50, 187.52}, {{2013, 1, 7}, 71.37, 154.21, 175.58}, {{2013, 1, 8}, 72.51, 149.66, 163.25}}; I want a DateListPlot with three graphs, so for a matrix formed by columns 1 and 2, one for columns 1 and 3, and 1 for columns 1 and 4. At the moment I'm using this code: data2 = Transpose[{data[[All, 1]], data[[All, 2]]}]; data3 = Transpose[{data[[All, 1]], data[[All, 3]]}]; data4 = Transpose[{data[[All, 1]], data[[All, 4]]}]; DateListPlot[{data2, data3, data4}, Joined -> True, Filling -> {3 -> {1}}] but I have a hunch that this can be done more efficiently. I don't like the Transpose s in particular. Any ideas? edit (for extra credit) What if I need to multiply the second column by 2, which in my solution is simp...