Skip to main content

make specific cluster


I have set of coordinates. I want to make clusters in which every point is within 1.5 distance unit of it's neighbor.


ex of point coordinates:


{{-12.945, 20.6509, 12.5901}, {-13.4452, 20.307, 111.626}, 

{-12.9731, 22.8458, 12.4215}, {-13.2381, 24.8167, 10.7147},
{-11.3668, 23.3908,11.8499}, {-11.6828, 23.7311, 10.8839},
{-13.3929, 21.1835, 9.86324}, {-11.5016, 21.3324, 10.1392},
{-12.3079, 22.096, 8.57246}, {-12.5268, 20.9679, 10.5444},
{-12.1951, 24.5423, 10.1807}, {-11.8887, 22.3883, 10.0751},
{-14.2529, 20.4808, 9.81084}, {-11.9876, 21.8094, 11.0478},
{-12.3718, 23.6176, 11.8266}, {-11.6179, 20.8324, 11.2154},
{-12.5927, 21.7492, 12.5087}, {-12.1665, 24.6649, 11.2909},
{-12.3854, 21.5571, 9.51876}, {-12.2237, 23.4278, 9.9787}}


what is the quickest way in Mathematica for this (for large data sets).


I tried this to find all points that are within mentioned distance:


Table[Select[List, EuclideanDistance[List[[i]], #] < 1.5 &], {i, 1, Length[[List]]}]

but now I have troubles to join all sets that have common elements.



Answer



Here is a possible alteernative, I was working on while Kuba posted his answer :-) I also started by using FixedPoint and the inner loop seems to work but the outer one is easier with While.


c = {{-12.945, 20.6509, 12.5901}, {-13.4452, 20.307, 
111.626}, {-12.9731, 22.8458, 12.4215}, {-13.2381, 24.8167,
10.7147}, {-11.3668, 23.3908, 11.8499}, {-11.6828, 23.7311,

10.8839}, {-13.3929, 21.1835, 9.86324}, {-11.5016, 21.3324,
10.1392}, {-12.3079, 22.096, 8.57246}, {-12.5268, 20.9679,
10.5444}, {-12.1951, 24.5423, 10.1807}, {-11.8887, 22.3883,
10.0751}, {-14.2529, 20.4808, 9.81084}, {-11.9876, 21.8094,
11.0478}, {-12.3718, 23.6176, 11.8266}, {-11.6179, 20.8324,
11.2154}, {-12.5927, 21.7492, 12.5087}, {-12.1665, 24.6649,
11.2909}, {-12.3854, 21.5571, 9.51876}, {-12.2237, 23.4278,
9.9787}};
MyClustering[data_List, distance_?NumericQ] :=
Module[{dataoriginal = data, res = {}, temp = {}},

While[dataoriginal =!= {},
temp = {};
AppendTo[res,
FixedPoint[(
Map[
Function[p,
temp = Join[temp,
Select[dataoriginal, EuclideanDistance[#, p] < distance &]];
dataoriginal = Complement[dataoriginal, temp]], #];
temp) &, {dataoriginal[[1]]}]]];

Return[res]]

Just few notes: dataoriginal is needed because I modify the original list and the argument of a function (data in that case) cannot be modified inside the function's body. For huge lists AppendTo is generally slow, so a possible alternative is


res = Join[{res}, FixedPoint[...]]


Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]