Skip to main content

bugs - Taylor expansion of a function containing QPochhammer[q, q, n]


I want to get the following series expansion:


Series[QPochhammer[q, q, 3], {q, 0,4}]


but in Mathematica 11.0, I obtain the following gibberish:


bad output


There weren't any problems of this kind in Mathematica 8.0.


The following example with the infinite product


Series[QPochhammer[q, q], {q, 0, 4}]

works perfectly fine, producing the series


good result


Documentation regarding QPochhammer can be found here.




Q: What causes this problem with finite products and how to avoid it?




Answer



The reason it doesn't work is because somewhere between v10.0 and v10.3, the seventh definition of QPochhammer was modified to check that the second argument does not depend on the expansion parameter.


To restore previous behavior, clear the seventh definition,


(*Triggers loading of definitions*)
Series[QPochhammer[0, x, 3], {x, 0, 1}];

(*Unprotect*)
Unprotect[QPochhammer];


QPochhammer /:
System`Private`InternalSeries[
HoldPattern[QPochhammer][System`SeriesDump`w_,
System`SeriesDump`q_,
System`SeriesDump`k_Integer?Positive], {System`SeriesDump`z_,
System`SeriesDump`p_, System`SeriesDump`n_Integer}] /;
Internal`DependsOnQ[System`SeriesDump`w, System`SeriesDump`z] && !
Internal`DependsOnQ[{System`SeriesDump`q, System`SeriesDump`p},
System`SeriesDump`z] =.


Then add the definition from earlier versions,


QPochhammer /: 
System`Private`InternalSeries[
HoldPattern[QPochhammer][System`SeriesDump`w_,
System`SeriesDump`q_,
System`SeriesDump`k_Integer?Positive], {System`SeriesDump`z_,
System`SeriesDump`p_, System`SeriesDump`n_Integer}] /;
Internal`DependsOnQ[System`SeriesDump`w, System`SeriesDump`z] :=
Module[{System`SeriesDump`lim, System`SeriesDump`ord,

System`SeriesDump`qq, System`SeriesDump`ww},
System`SeriesDump`lim =
System`SeriesDump`getExpansionPoint[System`SeriesDump`w,
System`SeriesDump`z,
System`SeriesDump`p]; (System`SeriesDump`ord =
Min[System`SeriesDump`k,
System`SeriesDump`AdjustExpansionOrder[System`SeriesDump`w,
System`SeriesDump`lim, System`SeriesDump`z,
System`SeriesDump`p, System`SeriesDump`n]];
System`SeriesDump`ww =

System`Private`InternalSeries[
System`SeriesDump`w, {System`SeriesDump`z, System`SeriesDump`p,
System`SeriesDump`n}];
System`SeriesDump`qq =
System`Private`InternalSeries[
System`SeriesDump`q, {System`SeriesDump`z, System`SeriesDump`p,
System`SeriesDump`n}];
1 + Plus @@
Table[(-System`SeriesDump`ww)^
System`SeriesDump`m System`SeriesDump`qq^

Binomial[System`SeriesDump`m, 2] QBinomial[
System`SeriesDump`k, System`SeriesDump`m,
System`SeriesDump`qq], {System`SeriesDump`m,
System`SeriesDump`ord}]) /; System`SeriesDump`lim === 0];

Protect[QPochhammer];

Now we get the desired behavior,


Series[QPochhammer[q, q, 3], {q, 0, 4}]



Desired result



Warning The seventh definition was modified in later releases probably because someone discovered that it leads to incorrect results in some cases. Proceed with caution.


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

list manipulation - Selecting multiple columns from a matrix?

Sample data: data = { {{2013, 1, 1}, 24.13, 167.67, 231.82}, {{2013, 1, 2}, 32.15, 170.92, 225.99}, {{2013, 1, 3}, 35.43, 172.68, 221.67}, {{2013, 1, 4}, 36.73, 173.05, 218.32}, {{2013, 1, 5}, 58.19, 165.96, 197.05}, {{2013, 1, 6}, 69.99, 163.50, 187.52}, {{2013, 1, 7}, 71.37, 154.21, 175.58}, {{2013, 1, 8}, 72.51, 149.66, 163.25}}; I want a DateListPlot with three graphs, so for a matrix formed by columns 1 and 2, one for columns 1 and 3, and 1 for columns 1 and 4. At the moment I'm using this code: data2 = Transpose[{data[[All, 1]], data[[All, 2]]}]; data3 = Transpose[{data[[All, 1]], data[[All, 3]]}]; data4 = Transpose[{data[[All, 1]], data[[All, 4]]}]; DateListPlot[{data2, data3, data4}, Joined -> True, Filling -> {3 -> {1}}] but I have a hunch that this can be done more efficiently. I don't like the Transpose s in particular. Any ideas? edit (for extra credit) What if I need to multiply the second column by 2, which in my solution is simp...

plotting - How to draw some 2D curves in a 3D plot?

I want to plot several 2D curves ( Sin[x] at y=0 , Cos[x] at y=1 ) in a 3D plot, what function should i use? f[x_, y_] := Piecewise[{{0, y 0}, {Sin[x], y == 0}}] g[x_, y_] := Piecewise[{{0, y 1}, {Cos[x], y == 1}}] Plot3D[{f[x, y], g[x, y]}, {x, 0, 10}, {y, 0, 10}] doesn't work. Any ideas? Answer ParametricPlot3D[{{Sin[u], 0, u}, {Cos[u], 1, u}}, {u, 0, 20}, BoxRatios -> 1, PlotRange -> {{-2, 2}, {-.5, 2}, {0, 20}}] === update - general thoughts === I've seen the comments to this question and a few other approaches to the waterfall (or wire) plot are given in this question: Plotting several functions . Also I cannot not mention one of my favorite Mathematica blogs - Archery with this post on the story of discovery of 1st pulsar and an its infamous graphics - code is given in the post: