Skip to main content

Improved interpolation of mostly-structured 3d data


This question arose in response to a comment by Leonid to my answer for this question. He noted that for unstructured grids, Interpolation can only use InterpolationOrder->1. For example:


data = Flatten[Table[{x, y, x^2 + y^2}, {x, -10, 10}, {y, -10, 10}], 1];
dataDelete = Delete[data, RandomInteger[{1, Length[data]}]]
intD = Interpolation[dataDelete]
(* Interpolation::udeg: Interpolation on unstructured grids is currently only supported for InterpolationOrder->1 or InterpolationOrder->All. Order will be reduced to 1. *)


which gives a result much worse than All-order Interpolation. So, here's my question:


For data that is largely structured, but is missing one (or a few?) grid points, is there any way to figure out where the grid is missing points? This would allow you to first use linear interpolation to find a good guess for the value of the function at the missing grid points, then add that grid point to the dataset, only to interpolate the whole thing after. Then the error in the interpolation will be localized to the reconstructed region. Something like


dataReconstructed=Append[dataDelete,Sequence @@ Flatten@{#, intD @@ #} & /@missingcoords]
intReconstructed = Interpolation[dataReconstructed]

A manual example:


todelete = RandomInteger[{1, Length[data]}];
dataDelete = Delete[data, todelete];
intD = Interpolation[dataDelete]
missingcoords = {data[[todelete, {1, 2}]]}


dataReconstructed = Append[dataDelete,Sequence @@ Flatten@{#, intD @@ #} & /@missingcoords]
intReconstructed = Interpolation[dataReconstructed]

Comparing these two methods using exact[x_, y_] := x^2 + y^2:


Plot3D[intD[x, y] - exact[x, y], {x, -10, 10}, {y, -10, 10}]

Mathematica graphics


has differences all over the interpolated region, worse at the missing point. But:


Plot3D[intReconstructed[x, y] - exact[x, y], {x, -10, 10}, {y, -10, 10}]


Mathematica graphics


is much better everywhere except for the missing points.


In order to do this for a set where I don't know which grid points are missing, is there a way to figure out where the missing grid points are in a mostly structured grid?



Answer



How to figure out where the missing grid points are... This maybe not as robust as it gets


Take your data


data = Flatten[Table[{x, y, x^2 + y^2}, {x, -10, 10}, {y, -10, 10}], 
1];
dataDelete = Delete[data, RandomInteger[{1, Length[data]}]];


and extract the domain coordinates


d = dataDelete[[All, ;; -2]];

Choose the step to be the commonest of the differences in each direction


step = #2@
First@Commonest[
Join @@ Differences /@ Sort /@ GatherBy[d, #]] & @@@ {
{First, Last},
{Last, First}

};

Choose the range, the limits, to be the minimum and maximum of all rows and coloumns


limits = Through@{Min, Max}[#] & /@ Transpose@d;

Take the complement of a perfect grid and your data grid


Complement[Tuples[Range @@ Transpose@limits], d]

I got {{-3, 6}}


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...