Skip to main content

Some time difficulty in a Manipulate program inside a DynamicModule


This work began at Set PlotLabel length.


slopeExplorer[fn_, {x_, xmin_, xmax_}, {y_, ymin_, ymax_}] :=
DynamicModule[{f, pta, ptb},
f[t_] = fn /. x -> t;

Manipulate[
pta = {a, f[a]};
ptb = {a, f'[a]};
Show[
Plot[{Tooltip[f[x]], Tooltip[f[a] + f'[a] (x - a)]}, {x, xmin,
xmax},
PlotStyle -> {Directive[Blue], Directive[Orange]},
PlotRange -> {ymin, ymax},
PlotLabel ->
Pane["Slope of tangent line = " <>

ToString[PaddedForm[N[f'[a]], {6, 2}]] <> "\n", 200]],
Plot[Tooltip[f'[x]], {x, xmin - 0.01, a},
PlotRange -> All,
PlotStyle -> Directive[Red, Dashed]],
Graphics[{
Gray, Line[{pta, ptb}],
Red, PointSize[Medium], Tooltip[Point[pta], pta],
Blue, Tooltip[Point[ptb], ptb]
}]
], {{a, xmin, "x"}, xmin, xmax, Appearance -> "Labeled"}

]
]

The following example seems to work perfectly.


slopeExplorer[2 x^3 - 3 x^2 - 36 x, {x, -5, 6}, {y, -150, 150}]

Moving the slider back and forth works smoothly. No hesitations.


Same thing with this example:


slopeExplorer[6/(1 + x^2), {x, -5, 5}, {y, -10, 10}]


No problems.


However, this example experiences difficulty:


slopeExplorer[(3 + x)/(1 - 3 x), {x, -5, 3}, {y, -10, 10}]

All is well and smooth and the slider moves to the right, but when I get near the vertical asymptote at x=1/3, problems start.



  1. Slider seems to lock up.

  2. A small spinning colored wheel starts up, then disappears.

  3. The cell bracket goes black for a moment.



Then all stops and I can select slider, but it starts up again.


Might have something to do with something happening at the vertical asymptote, or it just might ben my limited understanding of avoiding this type of difficulty in Manipulate procedures.


Any thoughts?



Answer



The problem is mostly due to the PlotRange -> All in the second Plot. Also added use of Exclusions


slopeExplorer[fn_, {x_, xmin_, xmax_}, {y_, ymin_, ymax_}] :=
DynamicModule[{f, fp, pta, ptb, poles},
f[t_] = fn /. x -> t;
fp[t_] = f'[t] // Simplify;
poles = t /. Solve[Denominator[f[t]] == 0, t, Reals];

If[Length[poles] > 0, Print[StringForm["pole at ``", Thread[x == poles]]]];
Manipulate[
pta = {a, f[a]};
ptb = {a, fp[a]};
Show[
Plot[{
Tooltip[f[x]],
Tooltip[f[a] + fp[a] (x - a)]},
{x, xmin, xmax},
PlotStyle -> {Blue, Orange},

PlotRange -> {ymin, ymax},
PlotLabel ->
Pane["Slope of tangent line = " <>
ToString[PaddedForm[N[fp[a]], {6, 2}]] <> "\n", 200],
Exclusions -> poles],
Plot[Tooltip[fp[x]], {x, xmin, a + 2 $MachineEpsilon},
PlotRange -> {ymin, ymax},
PlotStyle -> Directive[Red, Dashed],
Exclusions -> poles],
Graphics[{

Gray, Line[{pta, ptb}],
Red, PointSize[Medium], Tooltip[Point[pta], pta],
Blue, Tooltip[Point[ptb], ptb]}]],
{{a, xmin, "x"}, xmin, xmax, Appearance -> "Labeled"}]]

slopeExplorer[(3 + x)/((1 - 3 x) (x - 2)), {x, -5, 3}, {y, -10, 10}]

enter image description here


Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...

What is and isn't a valid variable specification for Manipulate?

I have an expression whose terms have arguments (representing subscripts), like this: myExpr = A[0] + V[1,T] I would like to put it inside a Manipulate to see its value as I move around the parameters. (The goal is eventually to plot it wrt one of the variables inside.) However, Mathematica complains when I set V[1,T] as a manipulated variable: Manipulate[Evaluate[myExpr], {A[0], 0, 1}, {V[1, T], 0, 1}] (*Manipulate::vsform: Manipulate argument {V[1,T],0,1} does not have the correct form for a variable specification. >> *) As a workaround, if I get rid of the symbol T inside the argument, it works fine: Manipulate[ Evaluate[myExpr /. T -> 15], {A[0], 0, 1}, {V[1, 15], 0, 1}] Why this behavior? Can anyone point me to the documentation that says what counts as a valid variable? And is there a way to get Manpiulate to accept an expression with a symbolic argument as a variable? Investigations I've done so far: I tried using variableQ from this answer , but it says V[1...