Skip to main content

differential equations - FEM-ception: Using output of NDSolve FEM as input in another FEM problem


After having solved a Stokes flow problem in Mathematica on a subdomain RegionCapillary, I would like to solve an advection-diffusion problem on a larger domain RegionShell which contains the previous domain. This means taking the InterpolatingFunction returned by NDSolve FEM for the Stokes problem and setting it to zero everywhere on RegionShell, so that the Stokes velocity field can be used in the advection term of the transport problem on RegionShell. The solution, produced by Comsol, shows concentration boundary layers:


enter image description here



The left picture shows a solution of the velocity field u of the Stokes problem u=0,p=μ2u solved on the domain RegionCapillary. The right pictures shows a solution of concentration field c from the advection-diffusion problem Peuc=2c solved on RegionShell. Let's see if I can retrieve the Comsol solution in Mathematica.


   RegionCapillary = 
RegionUnion[Rectangle[{0, 0.1}, {0.9, 0.2}],
Rectangle[{0, 0.8}, {0.9, 0.9}],
Rectangle[{0.8, 0.2}, {0.9, 0.9}] ];
RegionShell = Rectangle[{0, 0}, {1, 1}];

<< NDSolve`FEM`
StokesOp := {
-Inactive[Laplacian][ u[x, y], {x, y}] + D[ p[x, y], x],

-Inactive[Laplacian][ v[x, y], {x, y}] + D[ p[x, y], y],
(* incompressibility div u = 0 *)
Div[{u[x, y], v[x, y]}, {x, y}]
} ;

bcs := {
DirichletCondition[p[x, y] == 10^3, x == 0 && y > 0.5],
DirichletCondition[p[x, y] == 0, x == 0 && y < 0.5],
DirichletCondition[{u[x, y] == 0., v[x, y] == 0.}, True]
};


Clear[xVel, yVel, pressure];
AbsoluteTiming[{xVel, yVel, pressure} =
NDSolveValue[{StokesOp == {0, 0, 0}, bcs}, {u, v,
p}, {x, y} \[Element] RegionCapillary,

Method -> {"FiniteElement",
"InterpolationOrder" -> {u -> 2, v -> 2, p -> 1},
"MeshOptions" -> {"MaxCellMeasure" -> 10^-4}}
]];


DensityPlot[Sqrt[
xVel[x, y]^2 + yVel[x, y]^2], {x, y} \[Element]
RegionCapillary,
PlotRange -> All, PlotLabel -> "velocity magnitude",
PlotPoints -> 30] // Quiet

This code produces the expected Stokes flow solution:


enter image description here


Here is my attempt to tackle the reaction-diffusion problem:



   Pe = 10^2;
advectionOp :=
If[{x, y} \[Element] RegionCapillary,
Pe {xVel[x, y], yVel[x, y]}.Inactive[Grad][c[x, y], {x, y}], 0] -
Inactive[Laplacian][c[x, y], {x, y}]

bcs := {DirichletCondition[c[x, y] == 0, x == 0 && 0.8 < y < 0.9],
DirichletCondition[c[x, y] == 1, x > 0]};

AbsoluteTiming[

csol = NDSolveValue[{advectionOp ==
NeumannValue[0, x == 0 && ((0 < y < 0.8) || (0.9 < y < 1))],
bcs}, c, {x, y} \[Element] RegionShell,
Method -> {"FiniteElement", "InterpolationOrder" -> {c -> 2},
"MeshOptions" -> {"MaxCellMeasure" -> 10^-3}}]];
DensityPlot[csol[x, y], {x, y} \[Element] RegionShell,
PlotRange -> All, PlotLabel -> "x velocity", PlotPoints -> 30]

enter image description here


You can see that my advection term uc is practically ignored. In it, I am trying to ensure that u=0 if outside of RegionCapillary, but u taken from the previous NDSolve solution otherwise. You can see that my c=0 DirichletCondition diffuses but no advection happens.



Please help me to fix this. I suspect the main problem lies in the line


advectionOp := 
If[{x, y} \[Element] mr,
Pe {xVel[x, y], yVel[x, y]}.Inactive[Grad][c[x, y], {x, y}], 0] -
Inactive[Laplacian][c[x, y], {x, y}]

in which the InterpolatingFunctionscalled xVel, yVel are defined over the domain RegionCapillary



Answer



First, I think that DirichletCondition[{u[x, y] == 0., v[x, y] == 0.}, True] is not what you want, nor what you specified in COMSOL. I think you want something like this: DirichletCondition[{u[x, y] == 0., v[x, y] == 0.}, x > 0] Then we get:


RegionCapillary = 

RegionUnion[Rectangle[{0, 0.1}, {0.9, 0.2}],
Rectangle[{0, 0.8}, {0.9, 0.9}], Rectangle[{0.8, 0.2}, {0.9, 0.9}]];
RegionShell = Rectangle[{0, 0}, {1, 1}];

<< NDSolve`FEM`
StokesOp := {-Inactive[Laplacian][u[x, y], {x, y}] +
D[p[x, y], x], -Inactive[Laplacian][v[x, y], {x, y}] +
D[p[x, y], y],(*incompressibility div u=0*)
Div[{u[x, y], v[x, y]}, {x, y}]};


bcs := {DirichletCondition[p[x, y] == 10^3, x == 0 && y > 0.5],
DirichletCondition[p[x, y] == 0, x == 0 && y < 0.5],
DirichletCondition[{u[x, y] == 0., v[x, y] == 0.}, x > 0]};

Clear[xVel, yVel, pressure];
AbsoluteTiming[{xVel, yVel, pressure} =
NDSolveValue[{StokesOp == {0, 0, 0}, bcs}, {u, v,
p}, {x, y} \[Element] RegionCapillary,
Method -> {"FiniteElement",
"InterpolationOrder" -> {u -> 2, v -> 2, p -> 1},

"MeshOptions" -> {"MaxCellMeasure" -> 10^-4}},
"ExtrapolationHandler" -> {0. &, "WarningMessage" -> False}];]

For making the interpolating function 0. outside the region you could set the "ExtrapolationHandler" -> {0. &, "WarningMessage" -> False} like documented in the Extrapolation of Solution Domains section,


DensityPlot[
Sqrt[xVel[x, y]^2 + yVel[x, y]^2], {x, y} \[Element] RegionCapillary,
PlotRange -> All, PlotLabel -> "velocity magnitude",
PlotPoints -> 100, ColorFunction -> "TemperatureMap"]
{0.306492, Null}


enter image description here


The interpolating function returns 0 outside it's original region:


xVel[0.5, 0.5]
0.

Not sure if the Pe=10^2 is what is specified in COMSOL, if I use:


Pe = 100^2;

Thinks looks similar:


eqn = Pe {xVel[x, y], yVel[x, y]}.Grad[c[x, y], {x, y}] - 

Laplacian[c[x, y], {x, y}];

mesh = ToElementMesh[RegionShell, MaxCellMeasure -> 0.001(*,
"MeshElementType"\[Rule]TriangleElement*)]

bcs = {DirichletCondition[c[x, y] == 0, x == 0 && 0.8 < y < 0.9],
DirichletCondition[c[x, y] == 1, x > 0]};

AbsoluteTiming[
csol = NDSolveValue[{eqn == 0, bcs}, c, {x, y} \[Element] mesh];]


{0.527804, Null}

DensityPlot[csol[x, y], {x, y} \[Element] RegionShell,
PlotRange -> All, PlotLabel -> "x velocity", PlotPoints -> 100,
ColorFunction -> "TemperatureMap"]

enter image description here


Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...

What is and isn't a valid variable specification for Manipulate?

I have an expression whose terms have arguments (representing subscripts), like this: myExpr = A[0] + V[1,T] I would like to put it inside a Manipulate to see its value as I move around the parameters. (The goal is eventually to plot it wrt one of the variables inside.) However, Mathematica complains when I set V[1,T] as a manipulated variable: Manipulate[Evaluate[myExpr], {A[0], 0, 1}, {V[1, T], 0, 1}] (*Manipulate::vsform: Manipulate argument {V[1,T],0,1} does not have the correct form for a variable specification. >> *) As a workaround, if I get rid of the symbol T inside the argument, it works fine: Manipulate[ Evaluate[myExpr /. T -> 15], {A[0], 0, 1}, {V[1, 15], 0, 1}] Why this behavior? Can anyone point me to the documentation that says what counts as a valid variable? And is there a way to get Manpiulate to accept an expression with a symbolic argument as a variable? Investigations I've done so far: I tried using variableQ from this answer , but it says V[1...