Skip to main content

differential equations - Spurious DSolve Solution


Bug introduced in 8.0.4 or earlier, persisting through 12.0.


DSolve quickly returns solutions to the following PDE (which is the homogeneous portion of the PDE in question 130755).


s = Flatten@DSolve[D[l[w1, w2], w1] a w2 - D[l[w1, w2], w2] a w1 - l[w1, w2] == 0, 
l[w1, w2], {w1, w2}]
(* {l[w1, w2] -> E^(-(ArcTan[w1/Sqrt[w2^2]]/a)) C[1][1/2 (w1^2 + w2^2)],
l[w1, w2] -> E^(ArcTan[w1/Sqrt[w2^2]]/a) C[1][1/2 (w1^2 + w2^2)]} *)


However, an attempt to verify this result indicates that one of the two solutions is spurious.


FullSimplify[Unevaluated[D[l[w1, w2], w1] a w2 - D[l[w1, w2], w2] a w1 - l[w1, w2]] /. #] &
/@ s
(* {-((E^(-(ArcTan[w1/Sqrt[w2^2]]/a)) (w2 + Sqrt[w2^2]) C[1][1/2 (w1^2 + w2^2)])/w2),
(E^(ArcTan[w1/Sqrt[w2^2]]/a) (-w2 + Sqrt[w2^2]) C[1][1/2 (w1^2 + w2^2)])/w2} *)

The first term fails to vanish for w2 > 0, and the second term for w2 < 0. Executing SetOptions[Solve, Method -> Reduce] prior to DSolve in the hope of obtaining conditional answers produces the same result. Also, using the DSolve Assumptions option does not help. For instance,


sp = Flatten@DSolve[D[l[w1, w2], w1] a w2 - D[l[w1, w2], w2] a w1 - l[w1, w2] == 0, 
l[w1, w2], {w1, w2}, Assumptions -> w2 > 0]

(* {l[w1, w2] -> E^(-(ArcTan[w1/w2]/a)) C[1][1/2 (w1^2 + w2^2)],
l[w1, w2] -> E^(ArcTan[w1/w2]/a) C[1][1/2 (w1^2 + w2^2)]} *)

FullSimplify[Unevaluated[D[l[w1, w2], w1] a w2 - D[l[w1, w2], w2] a w1 - l[w1, w2]] /. #] &
/@ sp
(* {-2 E^(-(ArcTan[w1/w2]/a)) C[1][1/2 (w1^2 + w2^2)], 0} *)

Once again, one solution is spurious. In fact, the correct solution is


l[w1, w2] -> E^(-(ArcTan[w1, w2]/a)) C[1][1/2 (w1^2 + w2^2)]];
FullSimplify[Unevaluated[D[l[w1, w2], w1] a w2 - D[l[w1, w2], w2] a w1 - l[w1, w2]] /. %

(* 0 *)

My questions are, (1) is this a bug (as it appears to be)?, and (2) does a work-around exist (apart from changing independent variables to obtain an ODE instead)?


Addendum


As commented by xzczd, this problem also occurs in question 130596.




Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...