Skip to main content

front end - Making cells group


After reading rcollyer's post I'm still not able to understand how grouping rules work. Here is a problem I'm facing. What I want is to create a new title, section and subsection styles. I want the title to group everything below till the next title. The section should group everything below till the next section. To see what I mean, open up a new notebook. Go to Format > Edit Stylesheet....


On this stylesheet make a new cell. Then select this cell and go to Cell > Show Expression.


Here enter the following:


Cell[StyleData["MyTitle"],
CellGroupingRules->{"MyTitleGrouping", 0},
CounterIncrements->"MyTitle",

CounterAssignments->{{"MySection", 0}, {"MySubsection", 0}},
FontSize->26,
]

Once this has been entered now go to Cell > Show Expression to revert back. Let us create two more cells in the same fashion, one for the section and subsection.


Cell[StyleData["MySection"],
CellGroupingRules->{"MyTitleGrouping", 10},
CounterIncrements->"MySection",
CounterAssignments->{{"MySubsection", 0}},
CellFrameLabels->{{

Cell[
TextData[
CounterBox["MySection"], " -"], CellBaseline -> Baseline], Inherited}, {
Inherited, Inherited}},
FontSize->20,
]

Finally, the subsection:


Cell[StyleData["MySubsection"],
CellGroupingRules->{"MyTitleGrouping", 20},

CellFrameLabels->{{
Cell[
TextData[
CounterBox["MySection"], ".",
CounterBox["MySubsection"], " -"], CellBaseline -> Baseline],
Inherited}, {Inherited, Inherited}},
CounterIncrements->"MySubsection",
FontSize->16,
]


After creating those new styles, now we can use them, here is a screenshot of what I obtained if I use the "MyTitle", "MySection" and "MySubsection" styles.


enter image description here


Don't mind the text I entered there. The main point here is that there is no grouping.


How can I make it behave as the regular "Title", "Section" and "Subsection" styles?


enter image description here



Answer



You are inventing your own grouping types. If you open the Options Inspector and go to Cell Options -> General Properties -> CellGroupingRules the drop-down shows several options available: "NormalGrouping", "TitleGrouping", "SectionGrouping", "InputGrouping", "OutputGrouping", "GraphicsGrouping", "GroupTogetherGrouping", and "GroupTogetherNestedGrouping".


You have used "MyTitleGrouping" which is not part of the list. Per my previous question, what you are looking for is "TitleGrouping" for "MyTitle" and "SectionGrouping" for "MySection" and "MySubSection". Implementing these changes, your code becomes:


Cell[StyleData["MyTitle"],
CellGroupingRules->{"TitleGrouping", 0},

CounterIncrements->"MyTitle",
CounterAssignments->{{"MySection", 0}, {"MySubsection", 0}},
FontSize->26,
]

Cell[StyleData["MySection"],
CellGroupingRules->{"SectionGrouping", 10},
CounterIncrements->"MySection",
CounterAssignments->{{"MySubsection", 0}},
CellFrameLabels->{{

Cell[
TextData[
CounterBox["MySection"], " -"], CellBaseline -> Baseline], Inherited}, {
Inherited, Inherited}},
FontSize->20,
]

Cell[StyleData["MySubsection"],
CellGroupingRules->{"SectionGrouping", 20},
CellFrameLabels->{{

Cell[
TextData[
CounterBox["MySection"], ".",
CounterBox["MySubsection"], " -"], CellBaseline -> Baseline],
Inherited}, {Inherited, Inherited}},
CounterIncrements->"MySubsection",
FontSize->16,
]




Here's the end result, for a simple notebook:


enter image description here


Comments

Popular posts from this blog

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

What is and isn't a valid variable specification for Manipulate?

I have an expression whose terms have arguments (representing subscripts), like this: myExpr = A[0] + V[1,T] I would like to put it inside a Manipulate to see its value as I move around the parameters. (The goal is eventually to plot it wrt one of the variables inside.) However, Mathematica complains when I set V[1,T] as a manipulated variable: Manipulate[Evaluate[myExpr], {A[0], 0, 1}, {V[1, T], 0, 1}] (*Manipulate::vsform: Manipulate argument {V[1,T],0,1} does not have the correct form for a variable specification. >> *) As a workaround, if I get rid of the symbol T inside the argument, it works fine: Manipulate[ Evaluate[myExpr /. T -> 15], {A[0], 0, 1}, {V[1, 15], 0, 1}] Why this behavior? Can anyone point me to the documentation that says what counts as a valid variable? And is there a way to get Manpiulate to accept an expression with a symbolic argument as a variable? Investigations I've done so far: I tried using variableQ from this answer , but it says V[1...