Skip to main content

front end - Making cells group


After reading rcollyer's post I'm still not able to understand how grouping rules work. Here is a problem I'm facing. What I want is to create a new title, section and subsection styles. I want the title to group everything below till the next title. The section should group everything below till the next section. To see what I mean, open up a new notebook. Go to Format > Edit Stylesheet....


On this stylesheet make a new cell. Then select this cell and go to Cell > Show Expression.


Here enter the following:


Cell[StyleData["MyTitle"],
 CellGroupingRules->{"MyTitleGrouping", 0},
 CounterIncrements->"MyTitle",

 CounterAssignments->{{"MySection", 0}, {"MySubsection", 0}},
 FontSize->26,
]

Once this has been entered now go to Cell > Show Expression to revert back. Let us create two more cells in the same fashion, one for the section and subsection.


Cell[StyleData["MySection"],
 CellGroupingRules->{"MyTitleGrouping", 10},
 CounterIncrements->"MySection",
 CounterAssignments->{{"MySubsection", 0}},
 CellFrameLabels->{{

    Cell[
     TextData[
      CounterBox["MySection"], " -"], CellBaseline -> Baseline], Inherited}, {
   Inherited, Inherited}},
 FontSize->20,
]

Finally, the subsection:


Cell[StyleData["MySubsection"],
 CellGroupingRules->{"MyTitleGrouping", 20},

 CellFrameLabels->{{
    Cell[
     TextData[
      CounterBox["MySection"], ".", 
      CounterBox["MySubsection"], " -"], CellBaseline -> Baseline], 
    Inherited}, {Inherited, Inherited}},
 CounterIncrements->"MySubsection",
 FontSize->16,
]


After creating those new styles, now we can use them, here is a screenshot of what I obtained if I use the "MyTitle", "MySection" and "MySubsection" styles.


enter image description here


Don't mind the text I entered there. The main point here is that there is no grouping.


How can I make it behave as the regular "Title", "Section" and "Subsection" styles?


enter image description here



Answer



You are inventing your own grouping types. If you open the Options Inspector and go to Cell Options -> General Properties -> CellGroupingRules the drop-down shows several options available: "NormalGrouping", "TitleGrouping", "SectionGrouping", "InputGrouping", "OutputGrouping", "GraphicsGrouping", "GroupTogetherGrouping", and "GroupTogetherNestedGrouping".


You have used "MyTitleGrouping" which is not part of the list. Per my previous question, what you are looking for is "TitleGrouping" for "MyTitle" and "SectionGrouping" for "MySection" and "MySubSection". Implementing these changes, your code becomes:


Cell[StyleData["MyTitle"],
 CellGroupingRules->{"TitleGrouping", 0},

 CounterIncrements->"MyTitle",
 CounterAssignments->{{"MySection", 0}, {"MySubsection", 0}},
 FontSize->26,
]

Cell[StyleData["MySection"],
 CellGroupingRules->{"SectionGrouping", 10},
 CounterIncrements->"MySection",
 CounterAssignments->{{"MySubsection", 0}},
 CellFrameLabels->{{

    Cell[
     TextData[
      CounterBox["MySection"], " -"], CellBaseline -> Baseline], Inherited}, {
   Inherited, Inherited}},
 FontSize->20,
]

Cell[StyleData["MySubsection"],
 CellGroupingRules->{"SectionGrouping", 20},
 CellFrameLabels->{{

    Cell[
     TextData[
      CounterBox["MySection"], ".", 
      CounterBox["MySubsection"], " -"], CellBaseline -> Baseline], 
    Inherited}, {Inherited, Inherited}},
 CounterIncrements->"MySubsection",
 FontSize->16,
]



Here's the end result, for a simple notebook:


enter image description here


Comments

Post a Comment

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...
Post a Comment
Read more

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...
Post a Comment
Read more

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...
Post a Comment
Read more