Skip to main content

table - issue with Animate


I want to make a animation based on the dataset like


data = Flatten[Table[{x, y, x^2 - y^2}, {x, -3, 3}, {y, -3, 3}], 1];

I show this data using a ListPlot3D.


p2[θ_] := RotationTransform[θ, {0, 0, 1}]

When I use Table to generate the different images, it works fine.


test11 = Table[
ListPlot3D[p2[a][data] /. {x_, y_, z_} -> {x, y, z*a}, Mesh -> 5,

MeshStyle -> White, Axes -> {False, False, True},
PlotRange -> {{-4, 4}, {-4, 4}, {-10, 10}}], {a, -1, 1, 0.1}]

Export["anigraf2.GIF", test11, "DisplayDurations" -> 1]

When I use 'Animate' to create the same output, Mathematica stops responding en I have to restart the software.


Animate[ListPlot3D[p2[a][data] /. {x_, y_, z_} -> {x, y, z*a}, 
Mesh -> 5, MeshStyle -> White, Axes -> False,
PlotRange -> {{-4, 4}, {-4, 4}, {-10, 10}}], {a, -1, 1, 0.1},
AnimationDirection -> ForwardBackward, AnimationRunning -> True,

SaveDefinitions -> True]

Is there somebody who has suggestion for this issue?



Answer



For anything but the simplest of graphics objects, always avoid Animate and use ListAnimate instead.


The difference is that ListAnimate works on a pre-defined list of images to create an animation. All the rendering is done beforehand. With Animate, it attempts to do the rendering on the fly, when you are moving the slider.


So this will make the animation you are looking for,


data = Flatten[Table[{x, y, x^2 - y^2}, {x, -3, 3}, {y, -3, 3}], 1];
p2[θ_] := RotationTransform[θ, {0, 0, 1}];
imglist = Table[

ListPlot3D[p2[a][data] /. {x_, y_, z_} -> {x, y, z*a}, Mesh -> 5,
MeshStyle -> White, Axes -> {False, False, True},
PlotRange -> {{-4, 4}, {-4, 4}, {-10, 10}}]
, {a, -1, 1, 0.1}];
ListAnimate[
imglist,
AnimationDirection -> ForwardBackward, AnimationRunning -> True,
SaveDefinitions -> True]

Another option is to use Manipulate instead of Animate. Manipulate will render the 3D graphics using fewer points when you are moving the slider, giving you the changes quickly when it can at the expense of quality, and then generating the higher quality images when the slider stops moving. (Correct me if I am wrong here) I do not think that Animate does this.



So this runs relatively quickly on my machine,


Manipulate[
ListPlot3D[p2[a][data] /. {x_, y_, z_} -> {x, y, z*a}, Mesh -> 5,
MeshStyle -> White, Axes -> {False, False, True},
PlotRange -> {{-4, 4}, {-4, 4}, {-10, 10}}]
, {a, -1, 1, 0.05}]

enter image description here


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

list manipulation - Selecting multiple columns from a matrix?

Sample data: data = { {{2013, 1, 1}, 24.13, 167.67, 231.82}, {{2013, 1, 2}, 32.15, 170.92, 225.99}, {{2013, 1, 3}, 35.43, 172.68, 221.67}, {{2013, 1, 4}, 36.73, 173.05, 218.32}, {{2013, 1, 5}, 58.19, 165.96, 197.05}, {{2013, 1, 6}, 69.99, 163.50, 187.52}, {{2013, 1, 7}, 71.37, 154.21, 175.58}, {{2013, 1, 8}, 72.51, 149.66, 163.25}}; I want a DateListPlot with three graphs, so for a matrix formed by columns 1 and 2, one for columns 1 and 3, and 1 for columns 1 and 4. At the moment I'm using this code: data2 = Transpose[{data[[All, 1]], data[[All, 2]]}]; data3 = Transpose[{data[[All, 1]], data[[All, 3]]}]; data4 = Transpose[{data[[All, 1]], data[[All, 4]]}]; DateListPlot[{data2, data3, data4}, Joined -> True, Filling -> {3 -> {1}}] but I have a hunch that this can be done more efficiently. I don't like the Transpose s in particular. Any ideas? edit (for extra credit) What if I need to multiply the second column by 2, which in my solution is simp...

calculus and analysis - Integral of the Sinc product

Let us consider the following integral $$ B_n = \int_0^\infty \prod_{k=1,3,5,\dots}^n\frac{\sin (x/k)}{x/k}dx $$ By definition, Sinc[x] == Sin[x]/x , therefore B[n_?OddQ] := Integrate[Product[Sinc[x/k], {k, 1, n, 2}], {x, 0, Infinity}] B /@ Range[1, 13, 2] {Pi/2, Pi/2, Pi/2, Pi/2, Pi/2, Pi/2, Pi/2} OK, everything is fine. But... B[15] 467807924713440738696537864469 Pi/935615849440640907310521750000 What's going on? Answer As Eckhard wrote in comments B[n] is the n-th Borwein integral . (The letter B was not accidental :) ) This funny properties of Borwein integrals is related to the Fourier transform of Sinc function FourierTransform[Sinc[x], x, k] 1/2 Sqrt[Pi/2] (Sign[1 - k] + Sign[1 + k]) Plot[%, {k, -2, 2}, Filling -> 0] which is the box function. The result is $\pi/2$ while the sum $$ 1/3+1/5+\dots+1/n $$ B_n = \frac{\pi}{2} - \pi \bigg(\sum_{k=3,5,\ldots}^n\frac{1}{k} -1\biggr)^\frac{n-1}{2}\prod_{k=3,5,\dots}^n\frac{k}{k-1}. $$ For $n=15$ it is equal to $$ \frac{46780...