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implementation details - How does Mathematica solve a certain differential equation?


I was trying to solve a nonlinear differential equation with the following code.


DSolve[3*x^2/D[u[x, y], x] + 3*y^2/D[u[x, y], y] == -1, u, {x, y}]

And I got the following output:


{{u -> Function[{x, y}, x^3/(-1 + C[1]) - y^3/C[1] + C[2]]}}


I would like to see steps. So, I used the following code:


WolframAlpha["DSolve[3*x^2/D[u[x,y],x]+3*y^2/D[u[x,y],y]\[Equal]-1,u,{\
x,y}]", IncludePods -> "Input", AppearanceElements -> {"Pods"}, 
 PodStates -> {"Input__Show steps"}]

But this did not give steps. Is it possible to understand how mathematica solved this differential equation?



Answer



@Nasser's method seems to be what Mathematica does internally. The following gives hints of the steps taken, and one can see the elements of Nasser's solution. Some is left to the user to guess. The first code modifies Integrate to print itself out; the second uses Trace to see the calls to Integrate.


Block[{DSolve`print = Print},                                (* internal hook *)

 Internal`InheritedBlock[{Integrate}, Unprotect[Integrate];  (* alter Integrate to print itself *)
  i : Integrate[___] /; ! TrueQ[$in] := 
   Block[{$in = True}, Print["***Integrate= ", HoldForm[i]]; i];
  Protect[Integrate];
  DSolve[3*x^2/D[u[x, y], x] + 3*y^2/D[u[x, y], y] == -1, u, {x, y}]
  ]]

Mathematica graphics


This does something similar, but the Integrate commands are output at the end, not at the time they are called:


Block[{DSolve`print = Print},

 Trace[
  DSolve[3*x^2/D[u[x, y], x] + 3*y^2/D[u[x, y], y] == -1, u, {x, y}],
  _Integrate,
  TraceInternal -> True
  ]]

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