Skip to main content

animation - Export Animate command to MOV video


I'm trying to export a rather complex Animate command into a full-HD resolution video, but having no success so far. The animation has around 520 frames (the number of elements in the trajectory array). What I should be seeing is a tube object moving with a sphere object, and whilst I can see the animation is working with the Animate command, I cannot see the same results when I export the animation. I have tried different things but this just doesn't seem to work, I'm probably not using the export command in the right way. Instead of the 500~ frames trajectory of the tube and the sphere, I just see the animator moving from one side to other.


I'm using the Export function, in the following way:



Export["my_output.mov",animationObject,"QuickTime",ImageSize->{1920,1080}]

My animation object follows this pattern:


(*theta and phi work as a function of s (the only animated variable) to change the view point*)
theta = N[Table[q, {q, 0.1, 2 \[Pi], (2 \[Pi] - 0.1)/Length[trajectory]}]];
phi = N[Table[q, {q, 0.5 \[Pi], 2.5 \[Pi], 2 \[Pi]/Length[trajectory]}]];

Animate[
Show[
(*data is a static array of around 5000 points*)

ListPointPlot3D[(*my list plot options and data*)],

(*A tube *)
Graphics3D[{White, Thickness [0.01], Opacity[0.4],Tube[trajectory[[1 ;; s]]]}],

(*A sphere*)
Graphics3D[{Yellow, Sphere[{trajectory[[s]]}, {0.02, 0.02}]}],

(*Just showing some grids with 10 grid lines*)
FaceGrids -> {(*Specific options for the face grids to show more lines, etc*)},


(*ViewPoint changed according to the corresponding value of s in the theta and phi arrays*)
ViewPoint -> Dynamic[{Sin[theta[[s]]] Cos[phi[[s]]],Sin[theta[[s]]] Sin[phi[[s]]], Cos[theta[[s]]]}],
ViewAngle -> 50 Degree],

(*Animate Parameters*)
{s, 1, Length[trajectory], 1}, DisplayAllSteps -> True,AnimationRepetitions -> 1, AnimationRunning -> False]

I'm using Mathematica 8 student version.



Answer




Since your code is not running due to the lack of trajectory and data it's not possible to give a verified solution, but the tips should help too. What you have to keep in mind is



  • you don't need Animate because to export a movie, you can just give Export a list of images or graphics. Use Table in exact the same way where you have Animate and remove the Dynamic from your ViewPoint

  • your static ListPointPlot3D does never change but you call it for every new frame. Store this (e.g. with a With block) into a variable and use this

  • speaking of this: maybe it is better to create a list of images because they are usually faster to render than Graphics3D objects. This can be done by converting the Graphics3D you create with Rasterize[gr, "Image",...]. There you can specify your image size. If you only want to export it as movie, than it make in my opinion no difference, where you rasterize it.

  • on the other hand 500 images of HD-size use a bit of memory, so maybe you have to try different things here if you run out of mem.


Finally, if you really want to create a movie of high quality, where you don't care about movie-size, than it's maybe worth to antialias the images before putting them into the movie. If you use a high-compression in your movie, then you can skip this since it maybe will not be visible any more. If you create your list of graphics with


With[{lp = 
ListPointPlot3D[data,

PlotStyle -> Directive[PointSize[0.009], Opacity[0.6]],
PlotRange -> {{-0.6, 0.4}, {-0.4, 0.6}, {-0.5, 0.5}},
SphericalRegion -> True, RotationAction -> "Clip"]},
imgs = Table[
Show[Graphics3D[{White, Thickness[0.01], Opacity[0.4],
Tube[trajectory[[1 ;; s]]]}],
Graphics3D[{Yellow,
Sphere[{trajectory[[s]]}, {0.02,
0.02}]}], Background -> Automatic,
Boxed -> False,

BoxRatios ->
Automatic,
FaceGrids -> {{{0, -1, 0}, {Table[l, {l, -1, 1, 0.1}],
Table[l, {l, -1, 1, 0.1}]}}, {{0,
0, -1}, {Table[l, {l, -1, 1, 0.1}],
Table[l, {l, -1, 1, 0.1}]}}, {{1, 0,
0}, {Table[l, {l, -1, 1, 0.1}],
Table[l, {l, -1, 1,
0.1}]}}},
ViewPoint -> {Sin[theta[[s]]] Cos[phi[[s]]],

Sin[theta[[s]]] Sin[phi[[s]]], Cos[theta[[s]]]},
ViewAngle -> 50 Degree, ImageSize -> {1920, 1080}],
{s, 1, Length[trajectory], 1}]
];

You can do in the export


Antialias[g_Graphics3D] := Module[{
resolution = 72, factor = 2},
ImageResize[
Rasterize[g, "Image", ImageResolution -> factor*resolution],

Scaled[1/factor]]
]

Export["tmp/my_output.mov", Antialias /@ imgs]

Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]