Skip to main content

gui construction - How can I get "custom" controls to appear and behave like "default" controls in my Manipulate?



For various reasons I need to define some controls in my Manipulate with complex behaviors that are not (or at least I don't think can be) accomplished using the simple default syntax for Manipulate controls.


Thanks to some answers here, I have controls that support thee behaviors, but



  • I can't get them to appear in my Manipulate aligned and labeled like the default controls, and

  • one of the controls does not update its displayed value when I click on it.


For example with


Manipulate[
 Row@start,
 {{r2, "q", "R2"}, {"p", "m", "q", "y", "z"}, ControlType -> SetterBar, Appearance -> "Palette"},

 {{r3, "z", "Label R3"}, {"p", "m", "q", "y", "z"}, ControlType -> SetterBar, Appearance -> "Palette"},

 {{r4, "-"}, ControlType -> None},
 Row[{
   SetterBar[
    Dynamic[r4, If[# != "-", n = 4; start = Take[Join[start, {"A"}], n], n = 3; start = Take[start, n]] &],
    {"\[Beta]", "\[Gamma]", "-"},
    Appearance -> "Palette"]
 }],


 Column[{Dynamic[pop /@ Range[n] // Row, TrackedSymbols :> {n}]}], {x,None}, {n, None}, {start, None},

 Initialization :> (pop[i_] := With[{j = i}, PopupMenu[Dynamic[start[[j]]], CharacterRange["A", "Z"], ImageSize -> {45, 19}]]; start = ConstantArray["A", 3]; n = 3;)

 ]

I get



in which




  • the controls for r4 and the popup menus lack labels and do not align with the other (default style) controls, and

  • the r4 control does not reflect changes in the value of the variable.


How can I get these "custom" controls to appear and behave correctly in my Manipulate?



If there's a solution that uses "default" Manipulate control specification that I'm missing, that would be great, as would a solution that allows me to specify define and reuse a custom control (I have several that are similar to the popup control in that they involve several popups).



Answer



I do not understand everything the code is suppose to do, but passing the control as a pure function inside a variable declaration might give the desired behavior. The other change is the variable-setting function in the Dynamic for r4 was changed to actually set the value of r4 upon an update.


Manipulate[
 Row@start,

 {{r2, "q", "R2"}, {"p", "m", "q", "y", "z"}, 
  ControlType -> SetterBar, Appearance -> "Palette"},
 {{r3, "z", "Label R3"}, {"p", "m", "q", "y", "z"}, 
  ControlType -> SetterBar, Appearance -> "Palette"},
 {{r4, "-"}, 
  Row[{SetterBar[
      Dynamic[r4, 
       If[(r4 = #) != "-", n = 4; start = Take[Join[start, {"A"}], n],
          n = 3; start = Take[start, n]] &], {"\[Beta]", "\[Gamma]", 
       "-"}, Appearance -> "Palette"]}] &},

 {n, Column[{Dynamic[pop /@ Range[n] // Row, 
      TrackedSymbols :> {n}]}] &},
 {x, None}, {start, None},
 Initialization :> (pop[i_] := 
    With[{j = i}, 
     PopupMenu[Dynamic[start[[j]]], CharacterRange["A", "Z"], 
      ImageSize -> {45, 19}]]; start = ConstantArray["A", 3]; n = 3;)]

Comments

Post a Comment

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...
Post a Comment
Read more

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?
Post a Comment
Read more

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...
Post a Comment
Read more