Skip to main content

performance tuning - Speeding up an intrinsically sequential operation



I am new to Mathematica and I am trying to measure its performance on a fundamentally sequential procedure.




  1. It involves a function STEP that operates on a List and returns an updated List.




  2. Therefore I use a NestList on this operation. The STEP operation involves a sequential calculation per each item in the List. There is no way to avoid this sequential operation without changing the problem.




  3. Each subsequent operation of STEP needs to use the latest List. In fact, it involves a matrix multiplication involving the latest List. I used a table and individual assignments to make this work.





I see no way of rewriting this code, at least easily, but I also see that a naive MATLAB implementation with two FOR loops produces code that is 4-5X faster on my laptop.


Below is a minimal code that shows what I am trying to do, it really slows down for larger NM and stepcount.


Am I missing something obvious?


Edit: The matrix shown below is not identically zero in general, one could think of it is any random matrix whose diagonals are zero. Here, it is a trivial example chosen to show the structure of the code.


ClearAll["Global`*"]
SeedRandom[1];
NM = 5;
minitial = 2 RandomInteger[{}, NM] - 1.;

Matrix = IdentityMatrix[5] 0;
stepcount = 10^2;
STEP[m_] :=
Block[{md = m},
Table[md[[i]] =
Sign[Tanh[Matrix[[i, All]].md + RandomReal[{-1, 1}]]], {i, NM}];
md]
mm = (NestList[STEP[#] &, minitial, stepcount] + 1.)/2 // ArrayPlot

Edit: Just to clarify what I am trying to do, here is how it can be done in MATLAB. Please note that the for loops are unavoidable in this way of thinking.



for ii=1:NT
for jj=1:NM
I = Matrix(jj,:)*m
m(jj) = sign (tanh[I]- rand(-1,1))
end
mm(:,ii)=m;
end

Maybe there is a more efficient way of doing this in Mathematica than how I implemented it. Hope this clarifies the problem.



Answer




Using Compile is a straightforward way to speed up procedural code based on machine numbers:


OP's:


SeedRandom[1];
NM = 50;
minitial = 2 RandomInteger[{}, NM] - 1.;
Matrix = IdentityMatrix[NM] 0;
stepcount = 10^4;
STEP[m_] := Block[{md = m},
Table[md[[i]] = Sign[Tanh[Matrix[[i, All]].md + RandomReal[{-1, 1}]]],
{i, NM}]];

mm1 = (NestList[STEP[#] &, minitial, stepcount] + 1.)/2; // AbsoluteTiming
(* {1.4655, Null} *)

Compiled:


cf = Compile[{{minitial, _Real, 1}, {Matrix, _Real, 
2}, {stepcount, _Integer}},
Block[{md = minitial},
Rescale@Table[
If[i == 0, (* i = 0 probably isn't needed *)
md[[j]], (* except to conform with NestList *)

md[[j]] =
Sign[Tanh[Matrix[[j, All]].md + RandomReal[{-1, 1}]]]
],
{i, 0, stepcount}, {j, Length@minitial}]
](*, CompilationTarget -> "C"*)
];

SeedRandom[1];
NM = 50;
minitial = 2 RandomInteger[{}, NM] - 1.;

mm2 = cf[minitial, Matrix, stepcount]; // AbsoluteTiming
(* {0.162614, Null} *)

mm1 == mm2
(* True *)

Use CompilationTarget -> "C" and it speeds up by another factor of 2.


Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.