Skip to main content

notebooks - Why can't I change the style of a cell repeatedly?


I ran into this when I was working with an example from the Help Pages of V9. Cells is a new function added in V9. The following appears to work the first time it is evaluated in a notebook with nb assigned to some appropriate value, say, EvaluationNotebook[].


Scan[(CurrentValue[#, StyleNames] = "Title") &, Cells[nb, CellStyle -> "Section"]]

However, if I try again to change the cells affected by the first evaluation to another style or back to the original style, nothing changes. Neither this


Scan[(CurrentValue[#, StyleNames] = "Text") &, Cells[nb, CellStyle -> "Title"]] 

nor this


Scan[(CurrentValue[#, StyleNames] = "Section") &, Cells[nb, CellStyle -> "Title"]]  


has any effect.


For other CurrenValue targets such as FontSize, it's easy to change the value repeatedly.


 Scan[(CurrentValue[#, FontSize] = 100) &,  Cells[nb, CellStyle -> "Section"]]
Scan[(CurrentValue[#, FontSize] = 30) &, Cells[nb, CellStyle -> "Section"]]

Answer



It appears that it only works once because it messes up the cell expressions it modifies the first time it is evaluated.


I started with a notebook with several kinds of cells but only one text cell, which had the cell expresion


Cell["Some text", "Text"]


I evaluated


nb = EvaluationNotebook[];
Scan[(CurrentValue[#, StyleNames] = "Section") &, Cells[nb, CellStyle -> "Text"]]

and everything looked good -- the text cell was reformatted to a section cell. However, the cell expression was now


Cell["Some text", "Text", "Section"]

It should have been


Cell["Some text", "Section"]


So I think we are looking at a bug.


Comments

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....