Skip to main content

packages - How safe is Encode?


How safe is an encoded package (using locked, etc)?


If I don't specify a personal key, I understand that the encoding key must be somewhere in the Mathematica program itself, and so it is not a perfect system, but:



  • can we trust it for commercial deployment?


  • has someone of you ever heard of it being found?

  • do you know if there are backdoor to reverse the code, like shadowing the encode/decode system...? (don't want to know them, just checking how safe it is...)


If I specify a key, I understand that it becomes a stronger system, but:



  • how can the client use the app without me giving back the key (without him seeing the code -> I'm supplying the app, but with closed source)?

  • is there a workaround for this personal key system?

  • how do you typically do it, or see it done?


I heard of MX files being used, but at first glance, they look very version/system specific, and so kind of difficult to manage when the client updates his Mathematica, or player. Nevertheless:




  • are they safer than encode?

  • can they be mixed up with encode to become safer?


On other programming languages I use USB dongles:



  • do you know how it could be done with Mathematica (my program is 100% coded on Mathematica language)?

  • would I need to go through the new librarylink?


I know that these are lots of questions, but I cannot find a lot of info on this theme.




Answer



The documentation of Encode states:



No function is provided in Mathematica to convert encoded files back to their original form.



implying that an average user should not be able to view your proprietary code.


If you look at the example on the Encode doc page you see that Get is used to read back the Encoded Collatz package and Collatz works as intended. If you now type:


Definition[Collatz]

you get



Collatz[1]:={1}

Collatz[Collatz`Private`n_Integer]:=
Prepend[Collatz[3
Collatz`Private`n+1],Collatz`Private`n]/;OddQ[Collatz`Private`n]&&
Collatz`Private`n>0

Collatz[Collatz`Private`n_Integer]:=
Prepend[Collatz[Collatz`Private`n/2],Collatz`Private`n]
/;EvenQ[Collatz`Private`n]&&Collatz`Private`n>0


So, some or all of your code becomes visible.


Of course, you can use TagSet to prevent this:


Collatz /: Definition[Collatz] := ""

but I'd think there will be ways to get around that and other measures.


So, it doesn't seem that Encode is sufficient to keep your code proprietary. It might be a good way to prevent third parties from viewing your code during transport, though. In a quick search I couldn't find the type of encryption, so there's not much to say about its actual safety.


If you want to deploy your code in encoded form, your clients might have to use Mathematica Player Pro (or MMA itself) as I don't think the CDF-player reads encoded documents (it doesn't import and export documents at all, see the CDFplayer FAQ). There may be Digital Rights Management in future versions according to the same FAQ:



Can I put copy protection on my CDFs?



At the moment, we do not have Digital Rights Management (DRM) for CDF, but we are working on making it available. Contact us for more details when DRM support becomes available.





Update:


There was a discussion about DRM in the LinkedIn group Mathematica. Perhaps you could contact the guy who seemed to have a solution?


Comments

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....