Skip to main content

numerical integration - Proper use of arbitrary number of variables


So, I'm working on a project where the number of independent variables is not fixed.


Consider a problem of $N$ independent variables, $\boldsymbol{r}$.


I want to perform different things with them. Amongst them, I want to consider (multidimensional) integration, etc.


Variables definition



My first question regarding this topic, is the definition of the variables to perform algebraic manipulation. My first though was to use


variables[N_]:=Table[x[i],{i,1,N}]

However, in some situations, (e.g. with Block), I cannot use these variables as I use x1,x2,.... e.g.


Block[{x[1]=2},x[1]^2]

gives an error.


(my current naive solution is to use):


variables[N_] := Table[ToExpression["x" <> ToString[i]], {i, 1, N}];


Is there any more standard solution?


Sums, integrals


This question also holds for the problem of computing integrals for arbitrary dimensions.


How can I tell Mathematica to compute


Integrate[f[{r1,r2,...,rn}], {r1, 0, 1}, {r2, 0, g[r1]},...,{rN, 0, h[{r1,r2,...,"rN-1"}]}]

Most of the times I will be interested in numerically compute the integral, but nevertheless, how do I tell Mathematica? I tried the simple "naive"


Integrate[1, Table[{i, 0, 1}, {i, variables[3]}]]

but it gives an error.




Answer



You might use:


variables[n_, sym_String: "x"] := Unique @ Table[sym, {n}]

variables[5]

variables[5]

variables[3, "Q"]



{x1, x2, x3, x4, x5}

{x6, x7, x8, x9, x10}

{Q1, Q2, Q3}

Note the difference on the second call.


For work in Sum et al. you can leverage the fact that a plain Function evaluates its arguments:


vars = variables[7, "z"];


Sum[Multinomial @@ vars, ##] & @@ ({#, 0, 1} & /@ vars)


13700

Comments

Popular posts from this blog

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

What is and isn't a valid variable specification for Manipulate?

I have an expression whose terms have arguments (representing subscripts), like this: myExpr = A[0] + V[1,T] I would like to put it inside a Manipulate to see its value as I move around the parameters. (The goal is eventually to plot it wrt one of the variables inside.) However, Mathematica complains when I set V[1,T] as a manipulated variable: Manipulate[Evaluate[myExpr], {A[0], 0, 1}, {V[1, T], 0, 1}] (*Manipulate::vsform: Manipulate argument {V[1,T],0,1} does not have the correct form for a variable specification. >> *) As a workaround, if I get rid of the symbol T inside the argument, it works fine: Manipulate[ Evaluate[myExpr /. T -> 15], {A[0], 0, 1}, {V[1, 15], 0, 1}] Why this behavior? Can anyone point me to the documentation that says what counts as a valid variable? And is there a way to get Manpiulate to accept an expression with a symbolic argument as a variable? Investigations I've done so far: I tried using variableQ from this answer , but it says V[1...