Skip to main content

calculus and analysis - How to collect terms with z-derivative?


my equations are very long (several pages). Here I will provide simple example:


eq = (g[x, y, z, t])^2*D[D[f[x, y, z, t], {x, 1}] {z, 1}] + \[Alpha]*

f[x, y, z, t]*D[D[g[x, y, z, t], {y, 1}], {z, 2}] +
g[x, y, z, t]*D[D[f[x, y, z, t], {t, 1}] {z, 2}]+D[f[x,y,z,t],{z,2}]

So, it has several functions, constant parameters, and consists of the sum of some terms. Each term is the product of some number of these functions and it's derivatives.


I want to collect, or sort, these terms according to z-derivative. So, first, I want to sort these terms according to the highest z-derivative of the function f[x,y,z,t]. So, in the example above, first term should be g[x, y, z, t]*D[D[f[x, y, z, t], {t, 1}] {z, 2}]+D[f[x,y,z,t],{z,2}], as long as it has second derivatives of the function f[x,y,z,t] over z. After that it should be (g[x, y, z, t])^2*D[D[f[x, y, z, t], {x, 1}] {z, 1}], and then f[x, y, z, t]*D[D[g[x, y, z, t], {y, 1}], {z, 2}].


Note, that the derivative could be taken over several arguments, like g[x, y, z, t]*D[D[f[x, y, z, t], {t, 1}] {z, 2}].


I looked through the examples of Collect, but didn't find a way to specify z-derivative, as a second argument. Also it would be good, if you point out, how to show only the terms with z derivatives.


Thanks in advance, Mikhail



Answer



I'm sure there is an easier and shorter way of doing this so consider this a starting point.



A strange thing I noticed is that when I copied and pasted your equation into a notebook it turned into a list.


eq = g[x, y, z, t]^2*D[D[f[x, y, z, t], {x, 1}] {z, 1}] + 
α*f[x, y, z, t]*D[D[g[x, y, z, t], {y, 1}], {z, 2}] +
g[x, y, z, t]*D[D[f[x, y, z, t], {t, 1}] {z, 2}] +
D[f[x, y, z, t], {z, 2}]

Mathematica graphics


I continue to be mystified by this however we need to take it into account.


Step 1 - Strip curly brackets


eq = eq[[1]]



Mathematica graphics


Step 2 - Break it into parts


eqList = eq[[#]] & /@ Range[Length[eq]]


Mathematica graphics


This effectively breaks it at the plus sign.


Step 3 - Sort the parts


This is the significant portion. We will use the value of the zth derivative to do the sorting.


sortedEqList = 
Sort[eqList,
Total@Cases[#1,

Derivative[i_Integer, j_Integer, k_Integer, l_Integer][f | g][x,
y, z, t] -> k, {0, Infinity}] >
Total@Cases[#2,
Derivative[i_Integer, j_Integer, k_Integer, l_Integer][f | g][x,
y, z, t] -> k, {0, Infinity}] &]

Mathematica graphics


Step 4 - Join the sorted parts


If you merely rejoin the parts using Plus they will be sorted back to the original order so use Inactive.


Inactive[Plus] @@ sortedEqList


Mathematica graphics


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...