How can I automatically define a function inside my Mathematica code using a result (expression) that preceded the point of definition.
For example:
tt = x + y
x + y
f[x_, y_] := 2*tt
f[1, 1]
2 (x + y)
doesn't give $f$ as 2($x+y$) with $x$ and $y$ being variables here. So, instead of giving f[1,1]=2(1+1)=4 it gave 2(x+y) not recognizing that $x$ and $y$ are meant to be variables.
How can I define $f$ here so that it picks up its definition from the expression of $tt$ automatically, with $x$ and $y$ as variables?
The reason I need this is that it would save me manually copying and pasting the expression x+y into the function defintion, and would make my code run automatically even when tt gives different expressions.
Answer
Another option is to use = instead of :=
tt = x + y
f[x_, y_] = 2*tt
f[1, 1]
f[x, 4]
f[x, y]
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