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bugs - Random variables with transformed discrete distributions cannot be applied to Probability[] function?


I have two discrete uniform distributions over same support:


Dx = DiscreteUniformDistribution[{-8, 8}];  
Dy = DiscreteUniformDistribution[{-8, 8}];

I use random variables X ∼ Dx, Y ∼ Dy to model condition in some if-else clause in C code. For example,


if (3 * x + 1 > y) {
...
}


So, I model this condition by random event 3*X + 1 > Y. Then probability I look for is:


Probability[
x > y,
{Distributed[x, TransformedDistribution[3 * x + 1, Distributed[x, Dx]]],
Distributed[y, Dy]}
]

Unfortunately, Mathematica produces nothing. As for me, this is very strange behavior because Mathematica also cannot compute mean for the product distribution of {X, Y}. Maybe, this problem is caused by different support of X and Y.


How can I compute this probability?




Answer



The following computes the probability you asked for, but I'm at a loss to understand why your notation won't work. It seems correct to me.


Probability[
3 x + 1 > y, {Distributed[x, Dx], Distributed[y, Dy]}]

(*
==> 147/289
*)

The Probability / Distribution functions are quite young and hence not fully bulletproofed and I have encountered a number of bugs myself. I suppose/hope that in the next release they will be solved. I suggest you contact Wolfram support (support@wolfram.com). But perhaps someone else here may find out what's wrong.



A few of mine:


No random variates from PDFs that stem from multivariate distributions:


dist = ProbabilityDistribution[
PDF[BinormalDistribution[{0, 0}, {1, 1}, 0]][{x,
y}], {x, -Infinity, Infinity}, {y, -Infinity, Infinity}];
RandomVariate[dist]

This works for 3, but not for 5 (and higher):


Expectation[x,x\[Distributed] OrderDistribution[{GeometricDistribution[0.1], 3}, 3]]
Expectation[x,x\[Distributed] OrderDistribution[{GeometricDistribution[0.1], 5}, 5]]


The following crashes the kernel after a minute or so (so, DO NOT EXECUTE):


PDF[TransformedDistribution[Sin[u], u \[Distributed] NormalDistribution[0, 1]], 0]

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