Skip to main content

plotting - Making a presentable BarChart


I've been asked to reproduce a bar chart generated in Excel in Mathematica. The original Excel chart looks like this;


Excel chart



My Mathematica version looks like this;


Mathematica chart


There are a couple of things wrong that I'd like to fix;



  1. The BarChart and ListPlot overlay doesn't seem to match up.

  2. The ChartLabels seem to have disappeared on the BarChart.

  3. Is there a nice way to make the ticks on the left and right sides match up (like when the Excel chart matches 9 % on the left to 90 % on the right)?

  4. I can't get the box and line to center align to the text in the legend.


Questions 1 and 2 are what I really need to fix, but 3 and 4 would be nice to have. Any help would be appreciated.



Here's the code I used to generate my chart;


purple = RGBColor[97/255, 16/255, 106/255];
orange = RGBColor[245/255, 132/255, 31/255];
labels = 
  {
    "FY15 Q1/2", "FY15 Q3/4", "FY16 Q1/2", "FY16 Q3/4", 
    "FY17 Q1/Q2", "FY17 Q3/Q4", "FY18 Q1/2", "FY18 Q3/4"
  };
starvedTime = {7.55, 11.23, 8.58333, 6.88833, 4.65167, 1.89, 6.49833, 1.95};
satTime = {70.1483, 81.1467, 81.115, 86.5483, 84.6833, 90.685, 79.6017, 91.0133};


plot1 = BarChart[starvedTime, 
  PlotRange -> {0, 12}, 
  ChartStyle -> purple, 
  BaseStyle -> "Text", 
  Frame -> {True, True, True, False},
  FrameTicks -> {False, True}, 
  FrameLabel -> {None, Style["Smelter Starved Time (%)", "Text"], None, None}, 
  PlotLabel -> "Smelter Starved Time by 6 Month Period: Base Case", 
  ImageSize -> Large, 

  ChartLabels -> {Placed[Style[#, "Text"] & /@ labels, Below], None},
  AxesOrigin -> {0, 0}, 
  PlotRangePadding -> {0, 0}, 
  BarSpacing -> 1];

plot2 = ListPlot[satTime, 
 Joined -> True, 
 PlotRange -> {60, 100}, 
 PlotStyle -> orange, 
 Frame -> {False, False, False, True}, 

 FrameTicks -> {None, None, None, All}, 
 FrameLabel -> 
  {None, None, None, Style["Smelter Operating at Constraint Rate (%)", "Text"]}, 
 BaseStyle -> "Text", 
 GridLines -> {None, Automatic}, 
 GridLinesStyle -> Directive[Gray, Dashed],
 ImageSize -> Large];

box = Graphics[{purple, Rectangle[]}, ImageSize -> 12];
text = Style["   Smelter Starved (%)   ", "Text"];

line = Graphics[{orange, Line[{{0, 0.5}, {1, 0.5}}]}, ImageSize -> {30, Automatic}];
text2 = Text[Style["    % Time Smelter at Constraint Rate (%)       ", "Text"]];
legend = Row[{box, text, line, text2}];

Column[{Overlay[{plot1, plot2}], legend}, Alignment -> {Center, Center}]

Answer



Answers to your 4 questions step by step to see how each of these changes the composite plot:


1. The image padding around the two images differs so you need to set a fixed value for each. With ImagePadding -> {{50, 50}, {50, 10}} as an option for both plots I get this:


enter image description here


2. ChartLabels -> Placed[Style[#, "Text"] & /@ labels, Below],ImagePadding -> {{50, 50}, {20, 10}},



enter image description here


3. in plot #2 add PlotLabel -> ""


enter image description here


4. I almost always prefer Grid to Row:


box = Graphics[{purple, Rectangle[]}, ImageSize -> 12];
text = "Smelter Starved (%)";
line = Graphics[{orange, Line[{{0, 0.5}, {1, 0.5}}]}, ImageSize -> {30, Automatic}];
text2 = "% Time Smelter at Constraint Rate (%)";
legend = Grid[{{box, text, line, text2}}, Alignment -> {{Right, Left}, Center},
BaseStyle -> Directive[FontFamily -> "Arial"], Spacings -> {{0, 0.5, 2}, 0}];


enter image description here


Finishing touches


Bar chart plot ranges go from 0.5 to length of data + 0.5. So set the plot range of your bar chart to PlotRange -> {{0.5, 8.5}, {0, 12}} and for the list plot to PlotRange -> {{0.5, 8.5}, {60, 100}}. Now set your data range for ListPlot to be DataRange -> {1, 8}. This will ensure that the point coincide with the middle of your bars.


plot1 = BarChart[starvedTime, AspectRatio -> 1/GoldenRatio, 
   AxesOrigin -> {0, 0}, BarSpacing -> 1, 
   BaseStyle -> Directive[FontFamily -> "Arial"], 
   ChartLabels -> Placed[labels, Below], ChartStyle -> purple, 
   Frame -> {True, True, True, False}, 
   FrameLabel -> {None, "Smelter Starved Time (%)", None, None}, 

   FrameTicks -> {{#, "", {0, 0.01}} & /@ Range[0.5, 8.5, 1], {0, 3, 
      6, 9, 12}, None, None}, FrameTicksStyle -> Directive[Plain, 12], 
   GridLines -> {None, {3, 6, 9}}, 
   GridLinesStyle -> Directive[Gray, Dashed], 
   ImagePadding -> {{50, 50}, {20, 10}}, ImageSize -> 600, 
   LabelStyle -> Directive[Bold, 12], 
   PlotLabel -> 
    Style["Smelter Starved Time by 6 Month Period: Base Case", 13], 
   PlotRange -> {{0.5, 8.5}, {0, 12}}, PlotRangePadding -> 0, 
   Ticks -> None];


plot2 = ListPlot[satTime, AspectRatio -> 1/GoldenRatio, Axes -> False,
    BaseStyle -> Directive[FontFamily -> "Arial"], 
   DataRange -> {1, 8}, Frame -> {False, False, False, True}, 
   FrameTicks -> {None, None, None, {60, 70, 80, 90, 100}}, 
   FrameTicksStyle -> Directive[Plain, 12], 
   FrameLabel -> {None, None, None, 
     "Smelter Operating at Constraint Rate (%)"}, ImageSize -> 600, 
   ImagePadding -> {{50, 50}, {20, 10}}, Joined -> True, 
   LabelStyle -> Directive[Bold, 12], PlotRangePadding -> 0, 

   PlotRange -> {{0.5, 8.5}, {60, 100}}, PlotStyle -> orange, 
   PlotLabel -> Style["", 13]];

enter image description here


Note #1. there is scope for you to match the fonts of the Excel chart.


Note #2. Labeled could be used instead of Column.


Note #3. To completely match the Excel chart you actually need the grid lines to be used in the bar chart rather than the list plot.


Note #4. Added some ticks between the bars.


Note #5. Corrected labels: "FY17 Q1/Q2", "FY17 Q3/Q4",


Comments

Post a Comment

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]
Post a Comment
Read more

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]
Post a Comment
Read more

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....
Post a Comment
Read more