Skip to main content

graphs and networks - Styling a FlowGraph


I tried to re-style a flow graph found via FindMaximumFlow, but this seems not to work:


vertices = {"s", 1, 2, 3, 4, 5, 6, "t"};
flows = {40, 30, 10, 22, 30, 54, 50, 37, 17, 32};
edges = {"s" <-> 1, 1 <-> 2, 2 <-> 3, 3 <-> "t", "s" <-> 4,
4 <-> 5, 5 <-> 3, 2 <-> 6, 6 <-> 4, 6 <-> "t"};

then


flowGraph = Graph[vertices,

edges,
EdgeCapacity -> flows,
EdgeWeight -> flows,
VertexLabels -> Placed["Name", Center],
VertexSize -> Medium,
GraphLayout -> "LayeredEmbedding",
EdgeLabels -> Placed["EdgeWeight", Center],
EdgeLabelStyle -> Directive[Blue, Medium]];

Now determining the optimum:



ℱ = FindMaximumFlow[flowGraph, "s", "t", "OptimumFlowData"];

with


g = ℱ["FlowGraph"]

So far everything is fine. But styling with something like


ℱ["FlowGraph", GraphStyle -> "SmallNetwork"]

does not work. When doing a right-click in the output (of F["FlowGraph"]) the styling options are offered and this works fine, but not when applying directly. At the moment my workaround is extracting the adjacency matrix and process this matrix. But I would prefer to choose directly a style. Has anyone a hint how this could be done?



Answer




g = ℱ["FlowGraph"];
SetProperty[RemoveProperty[g, DeleteCases[PropertyList[g], GraphLayout]],
GraphStyle -> "SmallNetwork"]

Mathematica graphics


What is happening: GraphStyle >> Details says:



Direct settings of any of Graph options override base settings provided by GraphStyle.



And, as can be seen using



PropertyList[ℱ["FlowGraph"]]


{EdgeShapeFunction, EdgeStyle, EdgeWeight, GraphHighlight, GraphHighlightStyle, GraphLayout, GraphStyle, VertexCoordinates, VertexShape, VertexShapeFunction, VertexSize, VertexStyle, VertexWeight}



many of styling options are set in ℱ["FlowGraph"], and they need to be removed for GraphStyle to work.


Comments

Popular posts from this blog

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]