Skip to main content

list manipulation - Applying filters to data of the form {{x1,y1},{x2,y2},...}


When working with any kind of measurement data there is (at least) for me always a phase where I have to play around with different filters (such as MedianFilter, MeanFilter, LowpassFilter ...) to figure out how to improve my data in some aspect (filtering noise, detecting outliers, detecting edges...). Two things have always bugged me when using the build-in filter functions:




  1. filters expect simple list like {y1,y2,y3,y4} when (more often than not) measurement data is of the form {{x1,y1}, {x2, y2}, {x3, y3}, {x4, y4}} where $x_i$ is some index (e.g. time or frequency) and $y_i$ is the respective measurement (e.g. voltage or force)




  2. filters have a syntax of the form someFilter[data, parameters] and not an operator form someFilter[parameters][data]





This leads often to a Kuddelmuddel of [[]] mixed with a bunch of Transpose and/or intermediate (global) variables


What is a stylistically good way to deal with this?



Answer



The answer I came up with is


Clear@applyFilter;
applyFilter[filter_] := Function[data,
Module[{freq, value},
{freq, value} = Transpose@data;

Transpose[{freq, filter@value}]
]
];

applyFilter[filters__] := RightComposition @@ (applyFilter /@ {filters})

applyFilter[{filter_, n_}] := Nest[applyFilter[filter], # , n] &

The features are:





  1. Applying filters in operator form


    applyFilter[MedianFilter[#, 5] &] @ someData


  2. Chaining filters together


    myfilter = applyFilter[
    MedianFilter[#, 5] &,
    MeanFilter[#,2 ] &
    ]

    (*used with myfilter @ someData *)


  3. Multiple filter passes


    applyFilter[{MeanFilter[#, 2] &, numberOfPasses}]


and can be used on some example data


example = Transpose[{Range@100, Accumulate@(RandomVariate[NormalDistribution[0, 1], 100])}]


example data


with for instance a MedianFilter to flatten the peaks/remove outliers


applyFilter[MedianFilter[#, 3] &] @ example

median filter


or a MedianFilter followed up by a MeanFilter (this can be advantageous compared to using only a MeanFilter if there are huge outliers in the data)


applyFilter[MedianFilter[#, 3] &, MeanFilter[#, 2] &] @ example

median filter + mean filter


or multiple passes of some filter (1 pass through MedianFilter and 10 passes through MeanFilter)



applyFilter[MedianFilter[#, 3] &, {MeanFilter[#, 2] &, 10}] @ example

median + 10 passes mean


For me at least, something like applyFilter makes using the build-in filters a lot more user-friendy when experimenting with data.


Manipulate[
ListLinePlot[{
example,
applyFilter[MedianFilter[#, r] &, {MeanFilter[#, r1] &, n}]@example}],

{{r, 0, "Medianfilter radius"}, 0, 10, 1}, Delimiter,

{{n, 0, "Meanfilter passes"}, 0, 10, 1},
{{r1, 0, "Meanfilter radius"}, 0, 10, 1}]

gif


Comments

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...