Skip to main content

programming - Moving controls from Manipulate to a Palette ( or similar GUI object )


Consider the following snippet as a reference.


 DynamicModule[{}, 

Manipulate[
Graphics[
Translate[
GeometricTransformation[
{ Blue,
Polygon[{{0, 0}, {1, 0}, {1, 1}, {0, 1}}]
}, {{scx, 0}, {0, scy}}
],
Tuples[{Range[wi], Range[he]}] - 1
],

ImageSize -> 400 {1, 1}
],
{{scx, 1, "x scale"}, 0, 1},
{{scy, 1, "y scale"}, 0, 1},
{{wi, 1, "width"}, 1, 5, 1},
{{he, 1, "heigth"}, 1, 5, 1}
]
]

Mathematica graphics



A graphical drawing program with a lot of controls (buttons, sliders) would benefit (a lot) by freeing up space and moving controls to a Palette, or a similar construct. I am considering the redesign of a GUI and I am currently investigating the options and technical possibilities. - Looking at the reference code snippet (which is not the GUI in question, but makes asking the question - and answering! - so much easier) I have the following question. Is it possible to move (one of) the sliders to a Palette, or similar construct?



Answer



You can use the "wormhole" construct from "tutorial/AdvancedDynamicFunctionality" like this:


Manipulate[
Graphics[
Translate[
GeometricTransformation[{Blue,
Polygon[{{0, 0}, {1, 0}, {1, 1}, {0, 1}}]}, {{scx, 0}, {0,
scy}}], Tuples[{Range[wi], Range[he]}] - 1],
ImageSize -> 400 {1, 1}],

OpenerView[{Button["external",
CreateDialog[DynamicModule[{}, Column[{
Control[{{scx, 1, "x scale"}, 0, 1}],
Control[{{scy, 1, "y scale"}, 0, 1}],
Control[{{wi, 1, "width"}, 1, 5, 1}],
Control[{{he, 1, "heigth"}, 1, 5, 1}]
}], InheritScope -> True]
]],
Column[{
Control[{{scx, 1, "x scale"}, 0, 1}],

Control[{{scy, 1, "y scale"}, 0, 1}],
Control[{{wi, 1, "width"}, 1, 5, 1}],
Control[{{he, 1, "heigth"}, 1, 5, 1}]
}]}]

]

Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

list manipulation - Selecting multiple columns from a matrix?

Sample data: data = { {{2013, 1, 1}, 24.13, 167.67, 231.82}, {{2013, 1, 2}, 32.15, 170.92, 225.99}, {{2013, 1, 3}, 35.43, 172.68, 221.67}, {{2013, 1, 4}, 36.73, 173.05, 218.32}, {{2013, 1, 5}, 58.19, 165.96, 197.05}, {{2013, 1, 6}, 69.99, 163.50, 187.52}, {{2013, 1, 7}, 71.37, 154.21, 175.58}, {{2013, 1, 8}, 72.51, 149.66, 163.25}}; I want a DateListPlot with three graphs, so for a matrix formed by columns 1 and 2, one for columns 1 and 3, and 1 for columns 1 and 4. At the moment I'm using this code: data2 = Transpose[{data[[All, 1]], data[[All, 2]]}]; data3 = Transpose[{data[[All, 1]], data[[All, 3]]}]; data4 = Transpose[{data[[All, 1]], data[[All, 4]]}]; DateListPlot[{data2, data3, data4}, Joined -> True, Filling -> {3 -> {1}}] but I have a hunch that this can be done more efficiently. I don't like the Transpose s in particular. Any ideas? edit (for extra credit) What if I need to multiply the second column by 2, which in my solution is simp...

calculus and analysis - Integral of the Sinc product

Let us consider the following integral $$ B_n = \int_0^\infty \prod_{k=1,3,5,\dots}^n\frac{\sin (x/k)}{x/k}dx $$ By definition, Sinc[x] == Sin[x]/x , therefore B[n_?OddQ] := Integrate[Product[Sinc[x/k], {k, 1, n, 2}], {x, 0, Infinity}] B /@ Range[1, 13, 2] {Pi/2, Pi/2, Pi/2, Pi/2, Pi/2, Pi/2, Pi/2} OK, everything is fine. But... B[15] 467807924713440738696537864469 Pi/935615849440640907310521750000 What's going on? Answer As Eckhard wrote in comments B[n] is the n-th Borwein integral . (The letter B was not accidental :) ) This funny properties of Borwein integrals is related to the Fourier transform of Sinc function FourierTransform[Sinc[x], x, k] 1/2 Sqrt[Pi/2] (Sign[1 - k] + Sign[1 + k]) Plot[%, {k, -2, 2}, Filling -> 0] which is the box function. The result is $\pi/2$ while the sum $$ 1/3+1/5+\dots+1/n $$ B_n = \frac{\pi}{2} - \pi \bigg(\sum_{k=3,5,\ldots}^n\frac{1}{k} -1\biggr)^\frac{n-1}{2}\prod_{k=3,5,\dots}^n\frac{k}{k-1}. $$ For $n=15$ it is equal to $$ \frac{46780...