Skip to main content

numerical integration - What is the proper way to operate on interpolating functions?


I am trying to multiply an interpolating function by -1. If I do this Mathematica does not seem to allow any further operations. Bear with me while I generate the Interpolating Function in question. It is a derivative of the output of NDSolve.


Clear["Global`*"];
Remove["Global`*"];
center = Rectangle[{-.1, -.1}, {.1, .1}];
shield = Rectangle[{-1, -1}, {1, 1}];
reg = RegionDifference[shield, center];
uif = NDSolveValue[{\!\(
\*SubsuperscriptBox[\(\[Del]\), \({x, y}\), \(2\)]\(u[x, y]\)\) == 0,
DirichletCondition[u[x, y] == 0, x^2 + y^2 >= .5],

DirichletCondition[u[x, y] == 1, x^2 + y^2 < .5]},u, {x, y} \[Element] reg]

partialx = Derivative[1, 0][uif];
NIntegrate[partialx[.5, y], {y, -.5, .5}, AccuracyGoal -> 3]
Plot[partialx[x, -.5], {x, -1, 1}]

At this point everything is fine. NIntegrate and Plot work.


However, this code does not work.


partialxneg = -1*Derivative[1, 0][uif];
NIntegrate[partialxneg[.5, y], {y, -.5, .5}, AccuracyGoal -> 3]

Plot[partialxneg[x, -.5], {x, -1, 1}]

NIntegrate fails with



The integrand (-InterpolatingFunction[{{-1., 1.}, {-1., 1.}}, {4, 4225, 0, {1320, 0}, {3, 3}, {1 ,0}, 0, 0, 0, Automatic, {}, {}, False}, {NDSolveFEMElementMesh[{{-1., -1.}, {-1., -0.875}, <<47>>, {0.875, -1.}, <<1270>>}, <<2>>, {<<24>>[{{<<1>>}, <<49>>, <<94>>}]}]}, {0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0., 0.,0., 0., 0., 0., <<1270>>}, {Automatic}])[<<1>>] has evaluated to non-numerical values for all sampling points in the region with boundaries {{-0.5, 0.5}}. >>



Also, Plot does not plot anything.


All I did was multiply the derivative by -1.



Answer



This really has nothing to do with interpolating functions per se; it arises from the way Mathematica deals with functional expressions in general. Consider,



f = #^2 &; g = -1 f; h = (-1 #)& @* f; hx[x_] = -1 f[x];
{f[2], g[2], h[2], hx[2]}


{4, (-(#1^2 &))[2], -4, -4}

Mathematica simply doesn't recognize g as a function, but h, which is based on the composition of functions works fine. ( @* is the operator form of Composition).


Therefore, you could use


partialxneg = -1 # & @* Derivative[1, 0][uif]


or


partialxneg[x_, y_] = -1 (Derivative[1, 0][uif])[x, y]

With either of these definitions, you will get


Plot[partialxneg[x, -.5], {x, -1, 1}]

plot


But that's kind of silly when


Plot[-partialx[x, -.5], {x, -1, 1}]


will do the job.


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...