Skip to main content

probability or statistics - Faster method for CDF of Multinomial Distribution?


Take the following:


p= N@{459/10703, 1/973, 95/10703, 635/10703, 179/10703, 565/10703,
54/973, 474/10703, 794/10703, 548/10703, 52/1529, 1/10703,

61/973, 86/1529, 775/10703, 162/10703, 160/10703, 870/10703,
157/10703, 816/10703, 691/10703, 471/10703, 192/10703,
10/973, 307/10703};

q={5, 6, 8, 20, 5, 14, 15, 12, 14, 5, 16, 14, 9, 8, 14, 9, 17, 18,
6, 6, 7, 11, 14, 17, 15};

n=200;

CDF[MultinomialDistribution[n, p], q] // AbsoluteTiming


I gave up waiting and aborted.


Any ideas for a faster method in native Mathematica for multinomial distribution CDF?


Edit: I'll be adding a bounty as soon as it's available to stimulate ideas/answers.


Here's a more trivial test case to use for those interested with results/timings from loungebook. Even with this much simpler case, better than five orders of magnitude performance gain.


probs = {.15, .1, .05, .2, .35, .12, .03};
counts = {18, 16, 13, 20, 21, 12, 10};
n = 49;
ClearSystemCache[];
fast = multinomFastCDF2[n, probs, counts] // AbsoluteTiming

ClearSystemCache[];
mma = CDF[MultinomialDistribution[n, probs], counts] // AbsoluteTiming
Last@fast == Last@mma
First@mma/First@fast


{0.00393243, 0.897792}


{2526.37, 0.897792}


True


642446.





Answer



Came up with this, using N[{...},14] on the setting of p in the OP to get sufficient result precision, it finishes in a few tenths on the loungebook:


multinomFastCDF2[n_Integer, p_, q_] := If[n < 0 || n > Tr[q], 0,
FullSimplify[E n! Last@Fold[Take[ListConvolve[##, {1, -1}, 0], UpTo[n + 1]] &,
MapThread[Divide[Gamma[#2 + 1, #1], Gamma[#2 + 1]]
Normalize[Divide[E^-#1 #1^Range[0, #2], Range[0, #2]!], Total] &,
{p,q}]]]];

Arguments are the number of trials, category probabilities, and CDF vector to evaluate.



If anyone can come up with better, I'm all eyes...


Comments

Popular posts from this blog

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

What is and isn't a valid variable specification for Manipulate?

I have an expression whose terms have arguments (representing subscripts), like this: myExpr = A[0] + V[1,T] I would like to put it inside a Manipulate to see its value as I move around the parameters. (The goal is eventually to plot it wrt one of the variables inside.) However, Mathematica complains when I set V[1,T] as a manipulated variable: Manipulate[Evaluate[myExpr], {A[0], 0, 1}, {V[1, T], 0, 1}] (*Manipulate::vsform: Manipulate argument {V[1,T],0,1} does not have the correct form for a variable specification. >> *) As a workaround, if I get rid of the symbol T inside the argument, it works fine: Manipulate[ Evaluate[myExpr /. T -> 15], {A[0], 0, 1}, {V[1, 15], 0, 1}] Why this behavior? Can anyone point me to the documentation that says what counts as a valid variable? And is there a way to get Manpiulate to accept an expression with a symbolic argument as a variable? Investigations I've done so far: I tried using variableQ from this answer , but it says V[1...