Skip to main content

graphics3d - Dynamic ClipPlanes calculated from current ViewPoint


(This is a follow-up question to the answer found here.)


I would like to define a clip plane dynamically from the current ViewPoint of my Graphics3D. Based on the solution found in the link above, I would like to do something like this (where the ClipPlanes option depends on the ViewPoint variable vp):


DynamicModule[
{vp},
{vp} = Options[Graphics3D, ViewPoint][[All, 2]];
Graphics3D[{FaceForm[Red, Blue], Sphere[]}, Axes -> True, ViewPoint -> Dynamic[vp],

ClipPlanes -> {{Sequence@@vp,0}}, ClipPlanesStyle -> Directive[Opacity[.2], Blue]
]
]

Unfortunately this doesn't work, and I couldn't figure out how to do it.



Answer



I think this may be the behavior you desire. I am borrowing Kuba's modified ClipPanes specification. One should not need RawBoxes here I think but it does serve the purpose to get our Dynamic expression into the Front End box form.


DynamicModule[{vp},
{vp} = Options[Graphics3D, ViewPoint][[All, 2]];
Graphics3D[{FaceForm[Red, Blue], Sphere[]},

Axes -> True,
ViewPoint -> Dynamic[vp],
ClipPlanes -> RawBoxes @ Dynamic @ {{Sequence @@ Cross[vp, {0, 0, 1}], 1}},
ClipPlanesStyle -> Directive[Opacity[.2], Blue]
]
]

enter image description here


In Evaluation leak from Dynamic in Button's action John Fultz writes with fair authority:




Front end options, which includes all box options, can take Dynamic heads. That basically means that the FE will compute the value of the Dynamic and use it for the option. And that it will be updated whenever a Dynamic dependency updates.



Since:



  1. Graphic3D expression is transformed into a Graphics3DBox (as may be viewed with menu command Cell > Show Expression)

  2. ClipPlanes remains as an option therein


it stands to reason that this must work if we can keep our Dynamic option value unmolested, and RawBoxes serves to do that.


Comments

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....