Skip to main content

plotting - How to color a contour plot over a subset of colors displayed in the bar legend


This seems real easy but I can't find the answer. I have a few contour plots that I am combining and want to use only one bar legend that captures all the values. Given that I know the range of values, how to get the colors to correspond so that, say, if one plot only ranges over 1/3 of the total range, it only displays 1/3 of the range of colors. The following code only plots the BarLegend correctly but leaves the colors in the contour plot unchanged:


ContourPlot[X^2+Y^2,{X,-3,3},{Y,-3,3},PlotLegends->BarLegend[{"LakeColors",{0, 100}}, 10]]

Edit: I should have been more precise. Here is a more explicit example. The goal is to make the contour colors quantitatively consistent between the plots.


h1 = ContourPlot[X^2 + Y^2, {X, -3, 3}, {Y, -3, 3}, PlotLegends -> Automatic];
h2 = ContourPlot[X^2 + Y^2, {X, -5, 5}, {Y, -5, 5}, PlotLegends -> Automatic];

GraphicsRow[{h1, h2}, ImageSize -> 500]

As @David_Park mentions, I need to use ColorFunction. But I don't know how with ContourPlot.



Answer



From David's suggestion to use ColorFunctionScaling and Colorfunction, I realized that the default scaling of color functions is between 0 and 1, so they must be rescaled over the desired range. I add the legend manually at the end.


minVal = 0; maxVal = 50;
h1 = ContourPlot[X^2 + Y^2, {X, -3, 3}, {Y, -3, 3},
ColorFunctionScaling -> False,
ColorFunction -> (ColorData["LakeColors"][
Rescale[#, {minVal, maxVal}]] &)];

h2 = ContourPlot[X^2 + Y^2, {X, -5, 5}, {Y, -5, 5},
ColorFunctionScaling -> False,
ColorFunction -> (ColorData["LakeColors"][
Rescale[#, {minVal, maxVal}]] &)];
Legended[GraphicsRow[{h1, h2}, ImageSize -> 500],
BarLegend[{"LakeColors", {minVal, maxVal}}]]

Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...