May I restrict caching to disk when memory runs low?

An hour ago, I had to hard reset my laptop again because Mathematica froze the system again. When import a large file or make a mistake that produces huge arrays with complicated entries etc., I often see that the system becomes unresponsive. Holding the power button for seconds seems to be the only solution.

I was forced to do so about 20 times in recent 3 months, because of a project I was working at. Today, chkdsk had to start already when Windows was starting which I think is creepy. No errors found on the disk, thank God.

Is there a way to constrain this behavior so that it doesn't become hopeless? Some setting which makes Mathematica say "I give up, low memory" instead of doing the impossible and suicidal caching?

Answer

Use MemoryConstrained

MemoryConstrained[yourCode, memoryLimit, actionOnMemoryLimitOverflow]

Comments

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...

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