output formatting - Using Padding with Text and Style

Suppose that I use:

Text[Style["(1, 0, 0)", 12, Background -> White], {1, 1, 0}]

How can I put a few points of padding around the text?

Thanks to Jens:

Initialization cell:

Options[myText] = {Background -> White, Padding -> 1, FrameStyle -> None};

myText[s_, pos_, OptionsPattern[]] := 
 Text[Framed[Style[s, 12], Background -> OptionValue[Background], 
   FrameMargins -> OptionValue[Padding], 
   FrameStyle -> OptionValue[FrameStyle]], pos]

Image code using myText:

Show[

 ContourPlot3D[{z == Sqrt[x^2 + y^2]}, {x, -2.5, 2.5}, {y, -2.5, 
   2.5}, {z, 0, 2},
  ContourStyle -> {Yellow, Opacity[0.8]}, Mesh -> None],
 ParametricPlot3D[{r Cos[t], r Sin[t], 2}, {t, 0, 2 π}, {r, 0, 2},
   PlotStyle -> {Blue, Opacity[0.5]}, Mesh -> None],
 ParametricPlot3D[{r Cos[t], r Sin[t], 0}, {t, 0, 2 π}, {r, 0, 2},
   PlotStyle -> {LightBlue, Opacity[0.5]}, Mesh -> None],
 Graphics3D[{
   Red, Thick, Arrow[{{0, 0, 0}, {2, 2, 0}}],
   Black, PointSize[Large],

   Point[{{0, 0, 0}, 2 {Cos[Pi/4], Sin[Pi/4], 0}}],
   myText["r = 0", {0, -0.6, 0}],
   myText["r = 2", 2 {Cos[30 °], Sin[30 °], 0}],
   Red, Thick, 
   Arrow[{{Cos[Pi/4], Sin[Pi/4], 0}, {Cos[Pi/4], Sin[Pi/4], 2.5}}],
   Black, PointSize[Large],
   Point[{{Cos[Pi/4], Sin[Pi/4], 0}, {Cos[Pi/4], Sin[Pi/4], 
      1}, {Cos[Pi/4], Sin[Pi/4], 2}}],
   myText["z = r", {Cos[35 °], Sin[35 °], 0.8}],
   myText["z = 2", {Cos[35 °], Sin[35 °], 1.8}]

   }], AxesLabel -> {"x", "y", "z"}, 
 PlotRange -> {{-2.5, 2.5}, {-2.5, 2.5}, {0, 2.5}}
 ]

For some reason, I am getting frequent kernel beeps when running the cell containing the image code. I don't know why.

Answer

There are two alternatives I would suggest, depending on what your plans for the Background are. Here is an illustration:

Text[Pane[Style["(1, 0, 0)", 12, Background -> Yellow], 
  ImageMargins -> 10], {1, 1, 0}]

Text[Framed[Style["(1, 0, 0)", 12], Background -> Yellow, 
  FrameMargins -> 10, FrameStyle -> None], {1, 1, 0}]

The first solution uses a Pane, but this doesn't have a Background option so that you have to specify the background color in the Style command, as you already did. I changed it to yellow just for clarity.

The second solution assumes that you want the background to fill out the extra space that was created, too. This can be done with Frame because it allows the Background option. I then set FrameStyle -> None to make the result look otherwise indistinguishable from a Pane.

When used in Graphics3D, these two outputs look as follows:

To make this easier to use, just define something like this:

Options[myText] = {Background -> White, Padding -> 5, 
   FrameStyle -> None};

myText[s_, pos_, OptionsPattern[]] := 
 Text[Framed[Style[s, 12], Background -> OptionValue[Background], 
   FrameMargins -> OptionValue[Padding], 
   FrameStyle -> OptionValue[FrameStyle]], pos]


Graphics3D[myText["{1,0,0}", {0, 0, 0}], Background -> LightBlue]

The relevant options can be changed by adding them to in the invocation of myText. I used the name Padding for the option that you wanted, even though it's realized as FrameMargins internally.

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.

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