Skip to main content

plotting - 3D heatmap density plot


I have a set of data that looks like {{x1, y1, z1}, {x2, y2, z2}, ...} so it describes points in 3D space. I want to make a heatmap out of this data. So that points with a high density are shown as a cloud and marked with different colors dependend of the density.


In fact, I want the result of this script just for 3D:


data = RandomReal[1, {100, 2}];
SmoothDensityHistogram[data, 0.02, "PDF", ColorFunction -> "Rainbow", Mesh -> 0]


enter image description here



Answer



If you want to plot a distribution that is three dimensional then first you need to form it! SmoothDensityHistogram plots a smooth kernel histogram of the values $\{x_i,y_i\}$ but as we have three dimensional data here we need the function called SmoothKernelDistribution!


data = RandomReal[1, {1000, 3}];
dist = SmoothKernelDistribution[data];

Now you have got the probability distribution with three variables. So we can simply plot the PDF as a 3d contour plot using ContourPlot3D. Keep in mind that this function is reputed to be little slow.


ContourPlot3D[Evaluate@PDF[dist, {x, y, z}], {x, -2, 2}, {y, -2, 2}, {z, -2, 2}, 
PlotRange -> All, Mesh -> None, MaxRecursion -> 0, PlotPoints -> 160,
ContourStyle -> Opacity[0.45], Mesh -> None,

ColorFunction -> Function[{x, y, z, f}, ColorData["Rainbow"][z]],
AxesLabel -> {x, y, z}]

enter image description here


To cut through the contours I used the option!


RegionFunction -> Function[{x, y, z}, x < z || z > y]

In order to check that the data points density is responsible for the shape of the contours we can use Graphics3D


pic = Graphics3D[{ColorData["DarkRainbow"][#[[3]]],
PointSize -> Large, Point[#]} & /@ data, Boxed -> False];

Show[con, pic]

enter image description here


BR


EDIT


To follow up on the 2D example and get warm colours for higher densities


 data = RandomReal[1, {500, 3}];
dist = SmoothKernelDistribution[data];
ContourPlot3D[Evaluate@PDF[dist, {x, y, z}], {x, -2, 2}, {y, -2, 2},
{z, -2, 2},PlotRange -> All, Mesh -> None, MaxRecursion -> 0, PlotPoints -> 150,

ContourStyle -> Opacity[0.45], Contours -> 5, Mesh -> None,
ColorFunction -> Function[{x, y, z, f}, ColorData["Rainbow"][f/Max[data]]],
AxesLabel -> {x, y, z},
RegionFunction -> Function[{x, y, z}, x < z || z > y]]

Mathematica graphics


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?