Skip to main content

plotting - Scale coloring of ContourPlot


The answer given here solved how to use the same color scale across multiple plots within the function ListContourPlot. I can't for the life of me map this solution onto the function ContourPlot that I am using.


Say for example I have the code


r = Norm[{x, y}];
plot1 = Plot3D[{r^2, -r^2}, {x, -Pi, Pi}, {y, -Pi, Pi},
ColorFunction -> "ThermometerColors", BoxRatios -> {2, 2, 3}];
plot2 = ContourPlot[r^2, {x, -Pi, Pi}, {y, -Pi, Pi},
ColorFunction -> "ThermometerColors"];
GraphicsRow[{plot1, plot2}]


which gives me the plots. If you look at the code you will see that in the contour plot I am only plotting the positive solutions and so for consistency my plot should be contours that are shades of red.


How can I achieve this?



*****EDIT 1*****


kguler submitted an answer that solved this example question, but for a reason I can't understand it doesn't work in the actual system that I'm using. Here is my full code:


    Clear["Global`*"];
DynamicEvaluationTimeout -> Infinity;

(*Nearest neighbour vectors*)
{e1, e2,

e3} = # & /@ {{0, -1}, {Sqrt[3]/2, 1/2}, {-Sqrt[3]/2, 1/2}};

(*dispersion*)
w[theta_, phi_] := Module[{c1, c2, c3, fq},
{c1, c2, c3} =
1 - 3 Sin[theta]^2 Cos[phi - 2 Pi (# - 1)/3]^2 & /@ {1, 2, 3};
fq = Total[#[[1]] Exp[I q.#[[2]]] & /@ {{c1, e1}, {c2, e2}, {c3,
e3}}];
Sqrt[1 + 2 # Omega Norm[fq]] & /@ {1, -1}
]




Omega = 0.01;
q = {qx, qy};



(***Figure3a***)
{theta, phi} = {Pi/2, Pi/2};

dirac3a = {(2/Sqrt[3]) ArcCos[2/5], 4 Pi/3};
zoom = 0.005 Pi;

With[
{plotopts = {Mesh -> None, PlotStyle -> Opacity[0.7],
Ticks -> {{1.33, 1.34, 1.35}, {4.18, 4.19, 4.20}, Automatic},
BoxRatios -> {2, 2, 2}, PlotPoints -> 50, MaxRecursion -> 2,
AxesEdge -> {{-1, -1}, {1, -1}, {-1, -1}},
ColorFunction -> "ThermometerColors", LabelStyle -> Large,
ClippingStyle -> None, BoxStyle -> Opacity[0.5],

ViewPoint -> {1.43, -2.84, 1.13}, ViewVertical -> {0., 0., 1.}}},
figure3a = Plot3D[w[theta, phi],
{qx, dirac3a[[1]] - zoom, dirac3a[[1]] + zoom}, {qy,
dirac3a[[2]] - zoom, dirac3a[[2]] + zoom}, plotopts]
]


(***Figure3b***)
With[{plotopts = {Frame -> True,
FrameTicks -> {{{4.18, 4.19, 4.20}, None}, {{1.33, 1.34, 1.35},

None}}, ColorFunction -> "ThermometerColors",
LabelStyle -> Large, PlotRangePadding -> None,
ColorFunctionScaling -> False,
ColorFunction -> ColorData[{"ThermometerColors", {0.9996, 1.0004}}]
}
},
figure3b = ContourPlot[w[theta, phi][[1]],
{qx, dirac3a[[1]] - zoom, dirac3a[[1]] + zoom}, {qy,
dirac3a[[2]] - zoom, dirac3a[[2]] + zoom}, plotopts]
]


(***Figure3b legend***)

legend = {0.9996 + 0.0001 #, 0.9996 + 0.0001 #} & /@ {0, 1, 2, 3, 4,
5, 6, 7, 8};
figure3bLegend =
ArrayPlot[legend, ColorFunction -> "ThermometerColors",
DataRange -> {{0, 1}, {0.9996, 1.0004}},
FrameTicks -> {{0.9996, 0.9997, 0.9998, 0.9999, {1.0000, "1.0000"},
1.0001, 1.0002, 1.0003, 1.0004}, None}, AspectRatio -> 7,

LabelStyle -> Large]

where I have incorporated the suggestion, but it gives me a plot that is monochrome. The values 0.9996 and 1.0004 correspond to the maxima and minima.



What is going on here?



Answer



plot1 = Plot3D[{r^2, -r^2}, {x, -Pi, Pi}, {y, -Pi, Pi}, 
ColorFunctionScaling -> False,
ColorFunction -> ColorData[{"ThermometerColors", {-20, 20}}],
BoxRatios -> {2, 2, 3}];

plot2 = ContourPlot[r^2, {x, -Pi, Pi}, {y, -Pi, Pi},
ColorFunctionScaling -> False,
ColorFunction -> ColorData[{"ThermometerColors", {-20, 20}}]];

Legended[GraphicsRow[{plot1, plot2}], BarLegend[{"ThermometerColors", {-20, 20}}, 20]]

enter image description here


Update: For the specific example in OP's updated question, the following changes produce the desired result:


Change plotops appearing in the part generating figure3b to


plotopts = {Frame -> True, 

FrameTicks -> {{{4.18, 4.19, 4.20}, None}, {{1.33, 1.34, 1.35},
None}}, LabelStyle -> Large, ImageSize -> 400,
PlotRangePadding -> None, ColorFunctionScaling -> False,
ColorFunction -> ColorData[{"ThermometerColors", {0.9996, 1.0004}}]}

and use the same scaled colors in the ArrayPlot that generates the legend:


figure3bLegend = 
ArrayPlot[legend, ColorFunctionScaling -> False,
ImageSize -> {200, 350},
ColorFunction -> ColorData[{"ThermometerColors", {0.9996, 1.0004}}],

DataRange -> {{0, 1}, {0.9996, 1.0004}},
FrameTicks -> {{0.9996, 0.9997, 0.9998, 0.9999, {1.0000, "1.0000"},
1.0001, 1.0002, 1.0003, 1.0004}, None}, AspectRatio -> 7,
LabelStyle -> Large]

and add the option ImageSize->400 in plotops used in generation of figure3a.


With these changes


Row[{figure3a, figure3b, figure3bLegend}, Spacer[5]]

gives enter image description here



Comments

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....