Skip to main content

files and directories - How to get the directory of a package?


I have a package that I have placed in the $BaseDirectory\Applications directory so that Needs can find it. I have a logo in the directory that I will return when a function is called. However, when I call NotebookDirectory in the package I get the directory of the notebook (this seems like expected behavior). I've not been able to find a corresponding PackageDirectory function.


How do I get the directory of a package so I can load a resource (in this case a .jpg logo) to return to the calling notebook?


Update to show package and $InputFileName returns empty string


Update to show proper use of $InputFileName in package


The package saved as an .m file in $BaseDirectory\Applications is:


BeginPackage["MyTest`"];
packageDirectory::usage="Gets the directory of the this package.";

packageLogo::usage="Gets the logo of this package.";
testfoo::usage="does this work"
Begin["`Private`"];
(* $Input only has a value as the package is being loaded so capture that
value with `Set` in order to use it with `SetDelayed` later. *)
thisIsThePackageDirectory=$InputFileName//DirectoryName;
packageDirectory[]:=thisIsThePackageDirectory
packageLogo[]:=Import[FileNameJoin[{thisIsThePackageDirectory,"logo.jpg"}],"JPEG"]
testfoo[]:="some text"
End[];

EndPackage[];

The logo.jpg file is in the same directory as the .m package.


The notebook commands are as follows.


Needs["MyTest`"]
Names["MyTest`*"]
(* {"packageDirectory", "packageLogo", "testfoo"} *)
packageLogo[]
(* Logo image returned *)
packageDirectory[] // InputForm

(* "C:\\ProgramData\\Mathematica\\Applications\\MyTest.m" *)
testfoo[]
(* some text *)

Many thanks to @Szabolcs and @Ymareth.



Answer



FindFile will tell you which file will be loaded when you ask for a particular package with the backtick syntax.


DirectoryName will return the directory that contains a file.


Example:


In[1]:= FindFile["Combinatorica`"]


Out[1]= "/Applications/Mathematica 10.1.app/Contents/AddOns/Packages/Combinatorica/Kernel/init.m"



Update: This solution is probably better: in your package file, use $InputFileName to determine the location of the package file and save it into a variable that is private to the package. The use this variable with the function that shows the logo.


Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Adding a thick curve to a regionplot

Suppose we have the following simple RegionPlot: f[x_] := 1 - x^2 g[x_] := 1 - 0.5 x^2 RegionPlot[{y < f[x], f[x] < y < g[x], y > g[x]}, {x, 0, 2}, {y, 0, 2}] Now I'm trying to change the curve defined by $y=g[x]$ into a thick black curve, while leaving all other boundaries in the plot unchanged. I've tried adding the region $y=g[x]$ and playing with the plotstyle, which didn't work, and I've tried BoundaryStyle, which changed all the boundaries in the plot. Now I'm kinda out of ideas... Any help would be appreciated! Answer With f[x_] := 1 - x^2 g[x_] := 1 - 0.5 x^2 You can use Epilog to add the thick line: RegionPlot[{y < f[x], f[x] < y < g[x], y > g[x]}, {x, 0, 2}, {y, 0, 2}, PlotPoints -> 50, Epilog -> (Plot[g[x], {x, 0, 2}, PlotStyle -> {Black, Thick}][[1]]), PlotStyle -> {Directive[Yellow, Opacity[0.4]], Directive[Pink, Opacity[0.4]],