Skip to main content

time series - EventSeries v. TimeSeries


I have what technically should be an event series, spike times of a neuron. Here's a subset of the spiking data -


st = {2.60661, 4.39836, 5.01687, 6.09621, 6.62883, 6.93686, 7.31116, 8.14444, 8.56538, 9.11395}

If I whip this into a TimeSeries then I can easily Accumulate[] them to yield a counting function like so:


spikeData = TimeSeries[Table[1,Length[st]],{st}];
accSpikeData = Accumulate[spikeData];
Row[{ListPlot[spikeData, Filling -> Bottom],ListPlot[accSpikeData, Filling -> Bottom]}]


Mathematica graphics


But- If I do the same thing with an EventSeries instead...


spikeData = EventSeries[Table[1, Length[st]], {st}];
accSpikeData = Accumulate[spikeData];
Row[{ListPlot[spikeData, Filling -> Bottom], ListPlot[accSpikeData, Filling -> Bottom]}]

Mathematica graphics


And, indeed, looking at the data-


accSpikeData["Path"]
(* {{2.60661, 1}, {4.39836, Missing[]}, {5.01687, Missing[]}, {6.09621,

Missing[]}, {6.62883, Missing[]}, {6.93686, Missing[]}, {7.31116,
Missing[]}, {8.14444, Missing[]}, {8.56538, Missing[]}} *)

I'm not sure if this is a bug or 'intended behavior'. As I understand EventSeries it is simply a non-interpolating version of TimeSeries, and, of course I can do what I need here with a TimeSeries but was just wondering why even having EventSeries is a thing.



Answer



This is intended behaviour and here is why. Accumulate on TimeSeries or on EventSeries assumes that it accumulates according to every regular step on times. So in case of irregularly sampled TimeSeries it interpolates and in case of irregularly sampled EventSeries it creates Missing[] values. Examples:


In[41]:= data = {1, 2, 3, 4, 5};
Accumulate[data]

Out[42]= {1, 3, 6, 10, 15}


Create a TimeSeries with irregular time stamps:


In[43]:= ts1 = TimeSeries[data, {{1, 1.5, 3, 3.5, 4}}];

Now Accumulate will cause the values to be interpolated automatically:


In[44]:= Accumulate[ts1]["Path"]

Out[44]= {{1., 1.}, {1.5, 3.}, {3., 11.}, {3.5, 15.}, {4., 20.}}

This is coming from subsampling ts11:



In[49]:= ts11 = TimeSeriesResample[ts1];
Accumulate[ts11]["Path"]

Out[50]= {{1., 1.}, {1.5, 3.}, {2., 5.33333}, {2.5, 8.}, {3., 11.}, {3.5, 15.}, {4., 20.}}

Compare to accumulating the values of ts1 directly:


In[46]:= Accumulate[ts1["Values"]]

Out[46]= {1, 3, 6, 10, 15}


Create another TimeSeries forcing the irregular time stamps to be treated as sequentially regular:


In[47]:= ts2 = TimeSeries[data, {{1, 1.5, 3, 3.5, 4}}, TemporalRegularity -> True];

Now accumulating ts2 gives the expected answer equivalent to accumulating the original data:


In[48]:= Accumulate[ts2]["Values"]

Out[48]= {1, 3, 6, 10, 15}

EventSeries does not interpolate automatically hence Accumulate chokes on Missing[] and gives red flag that something is off. What you need is to Accumulate the values directly or set TemporalRegularity to True upon (re)construction.


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

calculus and analysis - Integral of the Sinc product

Let us consider the following integral $$ B_n = \int_0^\infty \prod_{k=1,3,5,\dots}^n\frac{\sin (x/k)}{x/k}dx $$ By definition, Sinc[x] == Sin[x]/x , therefore B[n_?OddQ] := Integrate[Product[Sinc[x/k], {k, 1, n, 2}], {x, 0, Infinity}] B /@ Range[1, 13, 2] {Pi/2, Pi/2, Pi/2, Pi/2, Pi/2, Pi/2, Pi/2} OK, everything is fine. But... B[15] 467807924713440738696537864469 Pi/935615849440640907310521750000 What's going on? Answer As Eckhard wrote in comments B[n] is the n-th Borwein integral . (The letter B was not accidental :) ) This funny properties of Borwein integrals is related to the Fourier transform of Sinc function FourierTransform[Sinc[x], x, k] 1/2 Sqrt[Pi/2] (Sign[1 - k] + Sign[1 + k]) Plot[%, {k, -2, 2}, Filling -> 0] which is the box function. The result is $\pi/2$ while the sum $$ 1/3+1/5+\dots+1/n $$ B_n = \frac{\pi}{2} - \pi \bigg(\sum_{k=3,5,\ldots}^n\frac{1}{k} -1\biggr)^\frac{n-1}{2}\prod_{k=3,5,\dots}^n\frac{k}{k-1}. $$ For $n=15$ it is equal to $$ \frac{46780...

list manipulation - Selecting multiple columns from a matrix?

Sample data: data = { {{2013, 1, 1}, 24.13, 167.67, 231.82}, {{2013, 1, 2}, 32.15, 170.92, 225.99}, {{2013, 1, 3}, 35.43, 172.68, 221.67}, {{2013, 1, 4}, 36.73, 173.05, 218.32}, {{2013, 1, 5}, 58.19, 165.96, 197.05}, {{2013, 1, 6}, 69.99, 163.50, 187.52}, {{2013, 1, 7}, 71.37, 154.21, 175.58}, {{2013, 1, 8}, 72.51, 149.66, 163.25}}; I want a DateListPlot with three graphs, so for a matrix formed by columns 1 and 2, one for columns 1 and 3, and 1 for columns 1 and 4. At the moment I'm using this code: data2 = Transpose[{data[[All, 1]], data[[All, 2]]}]; data3 = Transpose[{data[[All, 1]], data[[All, 3]]}]; data4 = Transpose[{data[[All, 1]], data[[All, 4]]}]; DateListPlot[{data2, data3, data4}, Joined -> True, Filling -> {3 -> {1}}] but I have a hunch that this can be done more efficiently. I don't like the Transpose s in particular. Any ideas? edit (for extra credit) What if I need to multiply the second column by 2, which in my solution is simp...