Skip to main content

broken code - Why Min cannot be used as constrains of NMinimize?



I met a strange problem when trying to do an optimization.


Initialization code,


goal = 2.;
vector = {1.0, 1.1, 1.2, 1.3, 1.4, 1.5};

f[m1_Real, m2_Real] := Block[{v},
v = Map[# + m1*Sin[Norm[{m1, m2}]] &, vector];
Clip[v, {0, goal}]];

g[m1_Real, m2_Real] := Max[(goal - f[m1, m2])/goal] + Norm[{m1, m2}];


where f is a vector function and g is a scaler function. I want to minimize g[m1,m2] with constrains 0.8 <= Min[f[m1,m2]] <= 1.0 and 0 <= m1 <= 2 && 0 <= m2 <=2. Despite this seems straightforward, a direct implementation is problematic,


counter = 0;
NMinimize[{
g[m1, m2],
And[0.8 <= Min[f[m1, m2]]/goal <= 1.0, 0 <= m1 <= 2, 0 <= m2 <= 2]
}, {m1, m2},
Method -> {"NelderMead", "Tolerance" -> .001},
StepMonitor :> (Print[++counter, ":\t", {m1, m2}])]


If we execute the code, an error message NMinimize::bcons will be shown, which tells us that the constrains are not in the valid format.


After a few tests I found out that the the problem is related to the command Min used in the first constrain 0.8 <= Min[f[m1, m2]]/goal <= 1.0. If we do not use Min then there will be no problem, i.e., 0.8 <= Evaluate[Norm[f[m1, m2]/goal]] <= 1.0 can be evaluated without any problem.


So it seems that Min is not valid for using as constrains with NMizimize (yet we can use Norm, Plus, etc.). But this is really inconvenient because I do need to use Min as part of the constrains. I wonder if we can fix this problem?



Answer



To solve your problem, let's first take a good look at the warning generated by your code:



NMinimize::bcons: The following constraints are not valid:
{0 <= m1, 0 <= m2, 0.8 <= 0.5 f[m1, m2], m1 <= 2, m2 <= 2, 0.5 f[m1, m2] <= 1.}.
Constraints should be equalities, inequalities, or domain
specifications involving the variables. >>


What have you found? Our constraints are not valid, yeah, we know that, but what else? Oh, we see the constraints have been displayed by Mathematica and the form of them have been slightly changed, um, that's understandable, and we can easily find the correspondence between them and their original, 0 <= m1 and 0 <= m2 and m1 <= 2 and m2 <= 2 are for 0 <= m1 <= 2 and 0 <= m2 <= 2, 0.8 <= 0.5 f[m1, m2] and 0.5 f[m1, m2] <= 1. are…… wait, where's the Min? Where did it go? Mathematica don't like it so she deleted it?


Of course not, Min disappeared because it has been calculated before f[m1, m2] become number lists. What happened here is just same as:


Clear[m1, m2]
Min@f[m1, m2]


f[m1, m2]

This can be approved by Trace:



NMinimize[{g[m1, m2], 
And[0.8 <= Min@f[m1, m2]/goal <= 1.0, 0 <= m1 <= 2, 0 <= m2 <= 2]},
{m1, m2},
Method -> {"NelderMead", "Tolerance" -> .001}] // Trace


{{{0.8 <= Min[f[m1, m2]]/goal <= 1. && 0 <= m1 <= 2 && 
0 <= m2 <= 2, {{{Min[f[m1, m2]], f[m1, m2]}…………

To fix your code, you can definite a new function that calculates only if its argument is a list:



min[x_List] := Min[x]

counter = 0;
(* I removed your Method option since it seems to be unnecessary. *)
NMinimize[{g[m1, m2],
And[0.8 <= min@f[m1, m2]/goal <= 1.0, 0 <= m1 <= 2, 0 <= m2 <= 2]},
{m1, m2},
StepMonitor :> (Print[++counter, ":\t", {m1, m2}])]



 {1.02036, {m1 -> 0.820357, m2 -> 2.34313*10^-8}}

Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?