bugs - What is the syntax to conditionally suppress plotting in version 9?

Bug introduced in 9.0 and fixed in 9.0.1

In Mathematica 7 it is very easy to conditionally suppress plotting of individual lines using If:

Plot[{
  If[x^2 < 2, x^2],
  If[Exp[x] > x^2, Exp[x]],
  If[False, x]                (* check recommended by Rahul *)
 },
 {x, -2, 2},
 PlotStyle -> Thick, Frame -> True]

enter image description here

Or more verbosely using Piecewise and Indeterminate:

Plot[{
  Piecewise[{{x^2, x^2 < 2}}, Indeterminate],
  Piecewise[{{Exp[x], Exp[x] > x^2}}, Indeterminate],
  Piecewise[{{x, False}}, Indeterminate]      (* check recommended by Rahul *)
  },
 {x, -2, 2},
 PlotStyle -> Thick, Frame -> True]

enter image description here

It is reported that neither method works in version 9.0.0 (at least on OSX.) Furthermore it is reported that my attempt using ConditionalExpression also fails:

Plot[{
  ConditionalExpression[x^2, x^2 < 2],
  ConditionalExpression[Exp[x], Exp[x] > x^2]
  },
 {x, -2, 2},
 PlotStyle -> Thick, Frame -> True]

Plotting a zero is reported to "work" but that is hardly a solution:

Plot[{
  Piecewise[{{x^2, x^2 < 2}}],
  Piecewise[{{Exp[x], Exp[x] > x^2}}]
  },
 {x, -2, 2},
 PlotStyle -> Thick, Frame -> True]

enter image description here

1. Is this indeed a bug in version 9.0.0?

2. Is there a workaround for the affected systems?

Answer

Since this bug seems to be tied directly to the appearance of Indeterminate as the only available function value in the plot range, it could perhaps be considered a work-around to replace Indeterminate by another "quantity" that behaves the same way as Indeterminate but doesn't cause the whole display of all other functions to be suppressed.

I tried the following, and it works on version 9.0.0:

Plot[{Piecewise[{{x^2,x^2<2}},Indeterminate],
  Piecewise[{{Exp[x],Exp[x]>x^2}},Indeterminate],
  Piecewise[{{x,False}},I]      (*modified check recommended by Rahul*)},
 {x,-2,2},
 PlotStyle->Thick,Frame->True]

Here, I used the imaginary unit I to produce the same effect as Indeterminate, and the remaining plots do still get displayed.

To make this more general, maybe one can use a replacement rule like this:

Plot[Evaluate[{Piecewise[{{x^2, x^2 < 2}}, Indeterminate], 
    Piecewise[{{Exp[x], Exp[x] > x^2}}, Indeterminate], 
    Piecewise[{{x, False}}, 
     Indeterminate]      (*modified check recommended by Rahul*)} /. 
   Indeterminate -> I], {x, -2, 2}, PlotStyle -> Thick, Frame -> True]

Comments

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.

Blog

Search This Blog