Skip to main content

sorting - SortBy misbehaving?


It maybe a stupid thing in the end but I'm stuck a couple of hours now.


I have a list of 2 points on the plane and I want to get the one with the biggest second coordinate. I thought I knew how SortBy operates. For example


SortBy[{{a, 1/2 (2 + Sqrt[2])}, {b, 1/2 (3 + Sqrt[2])}, {c, 1/2 (1 + Sqrt[2])}}, Function[{x}, x[[2]]]]

gives as expected the answer


{{c, 1/2 (1 + Sqrt[2])}, {a, 1/2 (2 + Sqrt[2])}, {b, 1/2 (3 + Sqrt[2])}}

and



SortBy[{{a, 1/2 (2 + Sqrt[2])}, {b, 1/2 (3 + Sqrt[2])}, {c, 1/2 (1 + Sqrt[2])}}, Function[{x}, -x[[2]]]]

gives as an answer


{{b, 1/2 (3 + Sqrt[2])}, {a, 1/2 (2 + Sqrt[2])}, {c, 1/2 (1 + Sqrt[2])}}

which is perfectly fine.


My list is


{{4/13 (-9 - Sqrt[3]), 6/13 (4 - Sqrt[3])}, {4/13 (-9 + Sqrt[3]), 6/13 (4 + Sqrt[3])}}

and the command



SortBy[{{4/13 (-9 - Sqrt[3]), 6/13 (4 - Sqrt[3])}, {4/13 (-9 + Sqrt[3]), 6/13 (4 + Sqrt[3])}}, Function[{x}, x[[2]]]]

gives the answer


{{4/13 (-9 - Sqrt[3]), 6/13 (4 - Sqrt[3])}, {4/13 (-9 + Sqrt[3]), 6/13 (4 + Sqrt[3])}}

which is the same as the answer I get from


SortBy[{{4/13 (-9 - Sqrt[3]), 6/13 (4 - Sqrt[3])}, {4/13 (-9 + Sqrt[3]), 6/13 (4 + Sqrt[3])}}, Function[{x}, -x[[2]]]]

Can someone explain to me what's going on? This drives me crazy.



Answer




I don't know exactly why Mathematica is giving a wrong result, but here's a workaround:


SortBy[{{4/13 (-9 - Sqrt[3]), 6/13 (4 - Sqrt[3])}, {4/13 (-9 + Sqrt[3]), 6/13 (4 + Sqrt[3])}}, 
-N @ #[[2]] &]

Mathematica graphics


That is, force Mathematica to sort by their numerical value.


OR you can use Sort instead:


Sort[{{4/13 (-9 - Sqrt[3]), 6/13 (4 - Sqrt[3])}, {4/13 (-9 + Sqrt[3]),
6/13 (4 + Sqrt[3])}}, #1[[2]] > #2[[2]] &]


Which gives the same result.


Comments

Popular posts from this blog

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...

plotting - Magnifying Glass on a Plot

Although there is a trick in TEX magnifying glass but I want to know is there any function to magnifying glass on a plot with Mathematica ? For example for a function as Sin[x] and at x=Pi/6 Below, this is just a picture desired from the cited site. the image got huge unfortunately I don't know how can I change the size of an image here! Answer Insetting a magnified part of the original Plot A) by adding a new Plot of the specified range xPos = Pi/6; range = 0.2; f = Sin; xyMinMax = {{xPos - range, xPos + range}, {f[xPos] - range*GoldenRatio^-1, f[xPos] + range*GoldenRatio^-1}}; Plot[f[x], {x, 0, 5}, Epilog -> {Transparent, EdgeForm[Thick], Rectangle[Sequence @@ Transpose[xyMinMax]], Inset[Plot[f[x], {x, xPos - range, xPos + range}, Frame -> True, Axes -> False, PlotRange -> xyMinMax, ImageSize -> 270], {4., 0.5}]}, ImageSize -> 700] B) by adding a new Plot within a Circle mf = RegionMember[Disk[{xPos, f[xPos]}, {range, range/GoldenRatio}]] Show...