Skip to main content

plotting - Building a Career Ladder Lattice (Follow up)


I want to thank you both for your help above. I'm going to abandon my quest for a number to label substitution using VertexRenderingFunction; because I need the labels to appear inside the yellow boxes as in:


LayeredGraphPlot[{"Tile & Marble Setter" -> "Construction Foreman", 
  "Construction Foreman" -> "Bricklayer", 
  "Stonemason" -> "Construction Foreman", 
  "Tile & Marble Setter" -> "Bricklayer", 
  "Bricklayer" -> "Tile & Marble Setter", 
  "Tile & Marble Setter" -> "Stonemason", 

  "Bricklayer" -> "Stonemason", "Stonemason" -> "Bricklayer", 
  "Apprentice Tile & Marble Setter" -> "Tile & Marble Setter", 
  "Apprentice Tile & Marble Setter" -> "Apprentice Bricklayer", 
  "Apprentice Tile & Marble Setter" -> "Apprentice Stonemason", 
  "Apprentice Bricklayer" -> "Apprentice Tile & Marble Setter", 
  "Apprentice Bricklayer" -> "Bricklayer", 
  "Apprentice Bricklayer" -> "Apprentice Stonemason", 
  "Apprentice Stonemason" -> "Apprentice Bricklayer", 
  "Apprentice Stonemason" -> "Stonemason", 
  "Helper/Finisher" -> "Apprentice Tile & Marble Setter", 

  "Helper/Finisher" -> "Apprentice Bricklayer", 
  "Helper/Finisher" -> "Apprentice Stonemason"}, 
 VertexLabeling -> True, 
 VertexCoordinateRules -> {{3, 6}, {6, 9}, {6, 6}, {9, 6}, {3, 3}, {6,
     3}, {9, 3}, {6, 0}}]

The question now becomes; how can I get single double-arrows joining:


Tile & Marble Setter <---> Bricklayer;


Bricklayer <---> Stonemason;


Apprentice Tile & Marble Setter <---> Apprentice Bricklayer;



Apprentice Bricklayer <---> Apprentice Stonemason;


in the above LayeredGraphPlot?


Thanks again!



Answer



VertexCoordinateRules apply to elements in the absolute order given, so by leading with 2 in 2 -> 1 you need to give its coordinate first.


titles = {"Construction Foreman",
   "Tile & Marble Setter",
   "Bricklayer",
   "Stonemason",
   "Apprentice Tile & Marble Setter",

   "Apprentice Bricklayer",
   "Apprentice Stonemason",
   "Helper/Finisher"};

LayeredGraphPlot[{2 -> 1, 3 -> 1, 4 -> 1, 2 -> 3, 3 -> 2, 2 -> 4, 3 -> 4, 4 -> 3, 
  5 -> 2, 5 -> 6, 5 -> 7, 6 -> 5, 6 -> 3, 6 -> 7, 7 -> 6, 7 -> 4, 8 -> 5, 8 -> 6, 
  8 -> 7},
 VertexCoordinateRules ->
   {{3, 6}, {6, 9}, {6, 6}, {9, 6}, {3, 3}, {6, 3}, {9, 3}, {6, 0}}, 
 VertexRenderingFunction -> 

   (Text[Style[titles[[#2]], Background -> White] ~Rotate~ (-20 °), #] &)
]

enter image description here


Comments

Post a Comment

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...
Post a Comment
Read more

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...
Post a Comment
Read more

list manipulation - Selecting multiple columns from a matrix?

Sample data: data = { {{2013, 1, 1}, 24.13, 167.67, 231.82}, {{2013, 1, 2}, 32.15, 170.92, 225.99}, {{2013, 1, 3}, 35.43, 172.68, 221.67}, {{2013, 1, 4}, 36.73, 173.05, 218.32}, {{2013, 1, 5}, 58.19, 165.96, 197.05}, {{2013, 1, 6}, 69.99, 163.50, 187.52}, {{2013, 1, 7}, 71.37, 154.21, 175.58}, {{2013, 1, 8}, 72.51, 149.66, 163.25}}; I want a DateListPlot with three graphs, so for a matrix formed by columns 1 and 2, one for columns 1 and 3, and 1 for columns 1 and 4. At the moment I'm using this code: data2 = Transpose[{data[[All, 1]], data[[All, 2]]}]; data3 = Transpose[{data[[All, 1]], data[[All, 3]]}]; data4 = Transpose[{data[[All, 1]], data[[All, 4]]}]; DateListPlot[{data2, data3, data4}, Joined -> True, Filling -> {3 -> {1}}] but I have a hunch that this can be done more efficiently. I don't like the Transpose s in particular. Any ideas? edit (for extra credit) What if I need to multiply the second column by 2, which in my solution is simp...
Post a Comment
Read more