Skip to main content

plotting - Building a Career Ladder Lattice (Follow up)


I want to thank you both for your help above. I'm going to abandon my quest for a number to label substitution using VertexRenderingFunction; because I need the labels to appear inside the yellow boxes as in:


LayeredGraphPlot[{"Tile & Marble Setter" -> "Construction Foreman", 
  "Construction Foreman" -> "Bricklayer", 
  "Stonemason" -> "Construction Foreman", 
  "Tile & Marble Setter" -> "Bricklayer", 
  "Bricklayer" -> "Tile & Marble Setter", 
  "Tile & Marble Setter" -> "Stonemason", 

  "Bricklayer" -> "Stonemason", "Stonemason" -> "Bricklayer", 
  "Apprentice Tile & Marble Setter" -> "Tile & Marble Setter", 
  "Apprentice Tile & Marble Setter" -> "Apprentice Bricklayer", 
  "Apprentice Tile & Marble Setter" -> "Apprentice Stonemason", 
  "Apprentice Bricklayer" -> "Apprentice Tile & Marble Setter", 
  "Apprentice Bricklayer" -> "Bricklayer", 
  "Apprentice Bricklayer" -> "Apprentice Stonemason", 
  "Apprentice Stonemason" -> "Apprentice Bricklayer", 
  "Apprentice Stonemason" -> "Stonemason", 
  "Helper/Finisher" -> "Apprentice Tile & Marble Setter", 

  "Helper/Finisher" -> "Apprentice Bricklayer", 
  "Helper/Finisher" -> "Apprentice Stonemason"}, 
 VertexLabeling -> True, 
 VertexCoordinateRules -> {{3, 6}, {6, 9}, {6, 6}, {9, 6}, {3, 3}, {6,
     3}, {9, 3}, {6, 0}}]

The question now becomes; how can I get single double-arrows joining:


Tile & Marble Setter <---> Bricklayer;


Bricklayer <---> Stonemason;


Apprentice Tile & Marble Setter <---> Apprentice Bricklayer;



Apprentice Bricklayer <---> Apprentice Stonemason;


in the above LayeredGraphPlot?


Thanks again!



Answer



VertexCoordinateRules apply to elements in the absolute order given, so by leading with 2 in 2 -> 1 you need to give its coordinate first.


titles = {"Construction Foreman",
   "Tile & Marble Setter",
   "Bricklayer",
   "Stonemason",
   "Apprentice Tile & Marble Setter",

   "Apprentice Bricklayer",
   "Apprentice Stonemason",
   "Helper/Finisher"};

LayeredGraphPlot[{2 -> 1, 3 -> 1, 4 -> 1, 2 -> 3, 3 -> 2, 2 -> 4, 3 -> 4, 4 -> 3, 
  5 -> 2, 5 -> 6, 5 -> 7, 6 -> 5, 6 -> 3, 6 -> 7, 7 -> 6, 7 -> 4, 8 -> 5, 8 -> 6, 
  8 -> 7},
 VertexCoordinateRules ->
   {{3, 6}, {6, 9}, {6, 6}, {9, 6}, {3, 3}, {6, 3}, {9, 3}, {6, 0}}, 
 VertexRenderingFunction -> 

   (Text[Style[titles[[#2]], Background -> White] ~Rotate~ (-20 °), #] &)
]

enter image description here


Comments

Post a Comment

Popular posts from this blog

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...
Post a Comment
Read more

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...
Post a Comment
Read more

plotting - Magnifying Glass on a Plot

Although there is a trick in TEX magnifying glass but I want to know is there any function to magnifying glass on a plot with Mathematica ? For example for a function as Sin[x] and at x=Pi/6 Below, this is just a picture desired from the cited site. the image got huge unfortunately I don't know how can I change the size of an image here! Answer Insetting a magnified part of the original Plot A) by adding a new Plot of the specified range xPos = Pi/6; range = 0.2; f = Sin; xyMinMax = {{xPos - range, xPos + range}, {f[xPos] - range*GoldenRatio^-1, f[xPos] + range*GoldenRatio^-1}}; Plot[f[x], {x, 0, 5}, Epilog -> {Transparent, EdgeForm[Thick], Rectangle[Sequence @@ Transpose[xyMinMax]], Inset[Plot[f[x], {x, xPos - range, xPos + range}, Frame -> True, Axes -> False, PlotRange -> xyMinMax, ImageSize -> 270], {4., 0.5}]}, ImageSize -> 700] B) by adding a new Plot within a Circle mf = RegionMember[Disk[{xPos, f[xPos]}, {range, range/GoldenRatio}]] Show...
Post a Comment
Read more