Skip to main content

plotting - Rasterized density plot with vector axes


I'm wondering if there is an easy way to get the plot below exported in a small PDF file?


The plot below is made in the following steps:



  1. Create a StreamPlot

  2. Create a DensityPlot, where the DensityPlot has to have a lot of sampling points in some cases !!

  3. Put the two of them together.



VortexAntivortex


Now whenever I save this as a PDF-file it becomes huge due to the large amount of sampling points.


Now I was wondering if it was possible to get this in a single (small !!) PDF-file? As far as I understand I need to rasterize the density plot and put the axes separately. Now I've seen some answers regarding this for a ListDensityPlot, but it doesn't seem to work for a DensityPlot. Whenever I try to put the PlotRangePadding to 0 weird things happen. Next to that I've also not been able to put the legend next to the plot after rasterization. Are there any hints on this ?


Code to reproduce the above example:


vx[x_, y_, d_] := -y*(1/((x - d)^2 + y^2) - 1/((x - 1/d)^2 + y^2)) + 
y*(1/((x + d)^2 + y^2) - 1/((x + 1/d)^2 + y^2))

vy[x_, y_,d_] := (x - d)/((x - d)^2 + y^2) - (x - 1/d)/((x - 1/d)^2 +
y^2) - (x + d)/((x + d)^2 + y^2) + (x + 1/d)/((x + 1/d)^2 + y^2)


v[x_, y_, d_] := Sqrt[( 4 d^2 (-1 + d^2)^2 ((1 + x^2)^2 + 2 (-1 + x^2) y^2 +
y^4))/(((d - x)^2 + y^2) ((d + x)^2 + y^2) ((-1 + d x)^2 +
d^2 y^2) ((1 + d x)^2 + d^2 y^2))]

part1 =
StreamPlot[{vx[x, y, 0.6], vy[x, y, 0.6]}, {x, -2, 2}, {y, -1.4,
1.4}, ImageSize -> 650, PlotRangePadding -> None,
FrameStyle -> Black, BaseStyle -> FontSize -> 22,
PerformanceGoal -> "Quality", StreamStyle -> "PinDart",

StreamPoints -> Fine, StreamScale -> .15,
AspectRatio -> ((1.4 - (-1.4))/(2 - (-2)))]

legend =
BarLegend[{"SunsetColors", {0, 15}}, LegendFunction -> "Panel",
LegendLabel ->
"|\!\(\*OverscriptBox[\(v\), \(\[RightVector]\)]\)|/(\[Kappa]/2\
\[Pi]R)", LabelStyle -> Directive[Bold, Black, 14],
LegendMargins -> 0, LegendMarkerSize -> 400]


part2 = DensityPlot[{v[x, y, 0.6]}, {x, -2, 2}, {y, -1.4, 1.4},
ImageSize -> 650, ColorFunction -> "SunsetColors",
PlotRangePadding -> None, FrameStyle -> Black,
BaseStyle -> FontSize -> 22, PerformanceGoal -> "Quality",
AspectRatio -> ((1.4 - (-1.4))/(2 - (-2))),
FrameLabel -> {"x/R", "y/R"},
PlotLabel ->
Style["The vortex-antivortex velocity field", Black, 30] ,
PlotRange -> {0, 15}, PlotPoints -> 200,
Epilog -> Style[Circle[{0, 0}, 1], {Thick, Dashed, White}],

PlotLegends -> Placed[legend, Right]]

plot = Show[part2, part1]

Answer



The rasterizeBackground function originally written by Szabolcs and then improved by Lukas Lang requires further minor update and improvement in order to get it working for your case in recent versions of Mathematica.


Here is a substantially more reliable version of that function which doesn't depend on the buggy AbsoluteOptions (I use here the workaround suggested by Carl Woll in this answer):


ClearAll[rasterizeBackground]
Options[rasterizeBackground] = {"TransparentBackground" -> False, Antialiasing -> False};
rasterizeBackground[g_Graphics, rs_Integer: 3000, OptionsPattern[]] :=
Module[{raster, plotrange, rect}, {raster, plotrange} =

Reap[First@Rasterize[
Show[g, Epilog -> {}, Prolog -> {}, PlotRangePadding -> 0, ImagePadding -> 0,
ImageMargins -> 0, PlotLabel -> None, FrameTicks -> None, Frame -> None,
Axes -> None, Ticks -> None, PlotRangeClipping -> False,
Antialiasing -> OptionValue[Antialiasing],
GridLines -> {Function[Sow[{##}, "X"]; None], Function[Sow[{##}, "Y"]; None]}],
"Graphics", ImageSize -> rs,
Background ->
Replace[OptionValue["TransparentBackground"], {True -> None, False -> Automatic}]],
_, #1 -> #2[[1]] &];

rect = Transpose[{"X", "Y"} /. plotrange];
Graphics[raster /. Raster[data_, _, rest__] :> Raster[data, rect, rest], Options[g]]]

rasterizeBackground[g_, rs_Integer: 3000, OptionsPattern[]] :=
g /. gr_Graphics :> rasterizeBackground[gr, rs]

With this version rasterization of your DensityPlot can be made as easy as follows:


plot = Show[rasterizeBackground[part2, 1000], part1]



output



The size of exported PDF file is reasonable and easily controllable by setting the raster size of the embedded image via the second argument of rasterizeBackground:


Export["plot.pdf", plot] // FileByteCount


490504



Additional example of use:




Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...