Skip to main content

formatting - How to fix Ticks in Gauges?



Ticks is an option for Gauges. I fail, however, to apply custom Ticks to Gauges. For instance, compare these two:


 {ThermometerGauge[50, {0, 100}, Ticks -> Automatic], 
 ThermometerGauge[50, {0, 100}, Ticks -> {0, 50, 100}]}

What you see is this:


enter image description here


No difference!


I also tried with the Horizontal- and VerticalGauge with the same success.


Do you know a workaround?


EDIT 11.07.13: I have seen the answers to my question. They all are good and fascinating, and in another case I will certainly use them. They do not answer my question though. For this reason I would like to give some more explanation of what I am really after. I will give it within an example of a different problem, where it is easy to obtain such a result.



So let us consider two simple plots. First is this


Plot[x, {x, -0.3, 0.3}, ImageSize -> 250]

second is this:


 Plot[x, {x, -0.3, 0.3}, Ticks -> {{0, 3/16, 1/4}, Automatic}, 
 ImageSize -> 250]

enter image description here


Here you can see it. The y axis in both plots is automatic - do not look at it. The x axis of the first plot is automatic for comparison, while the x axis of the second plot is what I am after. I would like to achieve the same on the ThermometerGauge, if possible by easy means. The easy means are here important, since looking at programs below I feel that it is easier to draw such a Gauge from scratch. For example, like this:


  thermo[x_] := Show[{

   Graphics3D[{Text[Style["-0.3", 12], {-0.15, 0, -0.3}], 
     Text[Style["0", 12], {-0.15, 0, 0}],
     Text[Style["3/16", 12], {0.14, 0, 3/16}] , 
     Text[Style["1/4", 12], {0.15, 0, 0.25}] , 
     Text[Style["0.3", 12], {-0.13, 0, 0.3}]}, 
    ViewPoint -> {0, -1.5, 0}, Boxed -> False, 
    ImageSize -> {120, 300}],
   Graphics3D[{LightBlue, Specularity[White, 20], Opacity[0.5], 
     Sphere[{0, 0, -0.4}, 0.11]}],
   Graphics3D[{Red, Specularity[White, 20], 

     Sphere[{0, 0, -0.4}, 0.1]}],
   Graphics3D[{LightBlue, Opacity[0.5], 
     Tube[{{0, 0, -0.4}, {0, 0, 0.35}}, 0.05]}],
   Graphics3D[{Red, Specularity[White, 20], 
     Cylinder[{{0, 0, -0.45}, {0, 0, x}}, 0.04]}],

   Graphics3D[{Thickness[0.015], 
     Line[{{-0.07, 0, #}, {-0.09, 0, #}}] & /@ 
      Table[i, {i, -0.3, 0.3, 0.1}]}],
   Graphics3D[{Red, Thickness[0.015], 

     Arrow[{{0.09, 0, 3/16}, {0.03, 0, 3/16}}], 
     Arrow[{{0.09, 0, 0.25}, {0.03, 0, 0.25}}]}]
   }]

Try it:


Manipulate[
 thermo[x], {{x, 0}, -0.3, 0.3}]

It looks as shown here:


enter image description here





Comments

Post a Comment

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]
Post a Comment
Read more

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]
Post a Comment
Read more

plotting - Adding a thick curve to a regionplot

Suppose we have the following simple RegionPlot: f[x_] := 1 - x^2 g[x_] := 1 - 0.5 x^2 RegionPlot[{y < f[x], f[x] < y < g[x], y > g[x]}, {x, 0, 2}, {y, 0, 2}] Now I'm trying to change the curve defined by $y=g[x]$ into a thick black curve, while leaving all other boundaries in the plot unchanged. I've tried adding the region $y=g[x]$ and playing with the plotstyle, which didn't work, and I've tried BoundaryStyle, which changed all the boundaries in the plot. Now I'm kinda out of ideas... Any help would be appreciated! Answer With f[x_] := 1 - x^2 g[x_] := 1 - 0.5 x^2 You can use Epilog to add the thick line: RegionPlot[{y < f[x], f[x] < y < g[x], y > g[x]}, {x, 0, 2}, {y, 0, 2}, PlotPoints -> 50, Epilog -> (Plot[g[x], {x, 0, 2}, PlotStyle -> {Black, Thick}][[1]]), PlotStyle -> {Directive[Yellow, Opacity[0.4]], Directive[Pink, Opacity[0.4]],
Post a Comment
Read more