graphics - How to position legends exactly where I want them?

I just noticed another plot legend question today and while user solutions to this, in particular code by @Jens, are IMO better than the built in solutions, exact positioning often still requires some trial and error.

How can I easily position my legends by way of locators?

Answer

Given that plot legend question keep arising I thought I would share my approach to legend positioning. I want to be able to use the legend as a locator and move it to the exact position I want it.

pt = Scaled[{0.5, 0.5}];

(* image padding for the ListLinePlot *)
{{l, r}, {b, t}} = {{20, 100}, {100, 10}};
(* width and height of the ListLinePlot *)

{w, h} = {400, 300};

opts = {AspectRatio -> 0.2, ImageMargins -> 0, ImagePadding -> 0, 
   ImageSize -> 30};

(* toy legend *)
legend = Column[{
    Grid[{{Graphics[{AbsoluteThickness[5], Red, 
         Line[{{0, 0}, {1, 0}}]}, opts], Style["label1", 16]}}, 
     Alignment -> {Center, Center}, Spacings -> 0.5],

    Grid[{{Graphics[{AbsoluteThickness[5], Blue, 
         Line[{{0, 0}, {1, 0}}]}, opts], Style["label2", 16]}}, 
     Alignment -> {Center, Center}, Spacings -> 0.5]
    }];

p1 = Overlay[{
   ListLinePlot[{{3, 6, 7, 2}, {1, 2, 3, 4}},
    AspectRatio -> h/w,
    ImageSize -> {w + l + r, h + b + t},
    ImagePadding -> {{l, r}, {b, t}},

    PlotStyle -> {{AbsoluteThickness[5], Red}, {AbsoluteThickness[5], 
       Blue}}],


 (* an empty graphic surrounding the ListLinePlot -- control this surrounding size by
 adjusting the image padding variables*)  
   Graphics[{}, AspectRatio -> (h + b + t)/(w + l + r), 
    ImageSize -> {w + l + r, h + b + t}, ImagePadding -> 0, 
    Epilog -> {Dynamic[Locator[Dynamic[pt], legend]]}]
   }, All, 2]

The legend can be positioned where you like. In this case I've started with large padding on the right and bottom. For column legends you may want to position to the right. For row legends on top or to the bottom.

Start:

enter image description here

move the legend:

enter image description here

You can see it working dynamically here.

To remove the dynamics from this and keep a static image:

p2 = p1 /. Locator[x_, y_] :> Inset[y, x] /. Dynamic :> Identity

Inset plots within a plot can be handled in a similar way -- namely as locators, there is no need for the surrounding graphic and the overlay in that case.

Comments

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.

Blog

Search This Blog