Skip to main content

linux - Install Mathematica 11.3 on 32bit Lubuntu 18.04 not work default to 64bit version


I'm recently installing Mathematica 11.3 on my 32bit Lubuntu 18.04.



The installer installs 64bit version of Mathematica in default, so I can not run the installed version.


Below is the error output of the installer:


WARNING: Failed to install WolframScript system integration.  See
/tmp/WolframScript-InstallErrors-8297 for more details.

But the error log file listed is empty when I cat it.


Below is the output when I run mathematica:


$ mathematica
can not find /usr/local/Wolfram/Mathematica/11.3/SystemFiles/FrontEnd/Binaries/Linux/Mathematica


There is not a directory named Linux, but a directory named Linux-x86-64.


After consulting the system requirement page , I'm sure that Mathematica 11.3 can run on 32bit Linux. But they only tested it on Ubuntu 12.04–17.10, not on Ubuntu 18.04.


So my question is:



  1. Is it possible that Mathematica 11.3 can not install correctly on 32bit Lubuntu 18.04?

  2. What compatibility library do I need to correctly install the 32bit version?

  3. Is there some option in the command line that I can use to choose the 32bit instead of the default 64bit version?


My system settings are as follows:


$ uname -a 

Linux **** 4.15.0-12-generic #13-Ubuntu SMP Thu Mar 8 06:23:34 UTC 2018 i686 i686 i686 GNU/Linux

$ lsb_release -a 
LSB Version:    core-9.20170808ubuntu1-noarch:security-9.20170808ubuntu1-    noarch
Distributor ID: Ubuntu
Description:    Ubuntu Bionic Beaver (development branch)
Release:    18.04

Codename: bionic



Answer




As of version 11.3.0, support for 32-bit Linux has been discontinued.


Only 64-bit Linux is supported, and the system requirements page has now been updated to reflect that


http://www.wolfram.com/mathematica/system-requirements.html


Additionally, I sent in a bug report since I believe the installer should have refused to run on a 32-bit system in the first place.


Comments

Post a Comment

Popular posts from this blog

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...
Post a Comment
Read more

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...
Post a Comment
Read more

What is and isn't a valid variable specification for Manipulate?

I have an expression whose terms have arguments (representing subscripts), like this: myExpr = A[0] + V[1,T] I would like to put it inside a Manipulate to see its value as I move around the parameters. (The goal is eventually to plot it wrt one of the variables inside.) However, Mathematica complains when I set V[1,T] as a manipulated variable: Manipulate[Evaluate[myExpr], {A[0], 0, 1}, {V[1, T], 0, 1}] (*Manipulate::vsform: Manipulate argument {V[1,T],0,1} does not have the correct form for a variable specification. >> *) As a workaround, if I get rid of the symbol T inside the argument, it works fine: Manipulate[ Evaluate[myExpr /. T -> 15], {A[0], 0, 1}, {V[1, 15], 0, 1}] Why this behavior? Can anyone point me to the documentation that says what counts as a valid variable? And is there a way to get Manpiulate to accept an expression with a symbolic argument as a variable? Investigations I've done so far: I tried using variableQ from this answer , but it says V[1...
Post a Comment
Read more