linux - Install Mathematica 11.3 on 32bit Lubuntu 18.04 not work default to 64bit version

I'm recently installing Mathematica 11.3 on my 32bit Lubuntu 18.04.

The installer installs 64bit version of Mathematica in default, so I can not run the installed version.

Below is the error output of the installer:

WARNING: Failed to install WolframScript system integration.  See
/tmp/WolframScript-InstallErrors-8297 for more details.

But the error log file listed is empty when I cat it.

Below is the output when I run mathematica:

$ mathematica
can not find /usr/local/Wolfram/Mathematica/11.3/SystemFiles/FrontEnd/Binaries/Linux/Mathematica

There is not a directory named Linux, but a directory named Linux-x86-64.

After consulting the system requirement page , I'm sure that Mathematica 11.3 can run on 32bit Linux. But they only tested it on Ubuntu 12.04–17.10, not on Ubuntu 18.04.

So my question is:

Is it possible that Mathematica 11.3 can not install correctly on 32bit Lubuntu 18.04?

What compatibility library do I need to correctly install the 32bit version?

Is there some option in the command line that I can use to choose the 32bit instead of the default 64bit version?

My system settings are as follows:

$ uname -a 

Linux **** 4.15.0-12-generic #13-Ubuntu SMP Thu Mar 8 06:23:34 UTC 2018 i686 i686 i686 GNU/Linux

$ lsb_release -a 
LSB Version:    core-9.20170808ubuntu1-noarch:security-9.20170808ubuntu1-    noarch
Distributor ID: Ubuntu
Description:    Ubuntu Bionic Beaver (development branch)
Release:    18.04

Codename: bionic

Answer

As of version 11.3.0, support for 32-bit Linux has been discontinued.

Only 64-bit Linux is supported, and the system requirements page has now been updated to reflect that

http://www.wolfram.com/mathematica/system-requirements.html

Additionally, I sent in a bug report since I believe the installer should have refused to run on a 32-bit system in the first place.

Comments

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

calculus and analysis - Integral of the Sinc product

Let us consider the following integral $$ B_n = \int_0^\infty \prod_{k=1,3,5,\dots}^n\frac{\sin (x/k)}{x/k}dx $$ By definition, Sinc[x] == Sin[x]/x , therefore B[n_?OddQ] := Integrate[Product[Sinc[x/k], {k, 1, n, 2}], {x, 0, Infinity}] B /@ Range[1, 13, 2] {Pi/2, Pi/2, Pi/2, Pi/2, Pi/2, Pi/2, Pi/2} OK, everything is fine. But... B[15] 467807924713440738696537864469 Pi/935615849440640907310521750000 What's going on? Answer As Eckhard wrote in comments B[n] is the n-th Borwein integral . (The letter B was not accidental :) ) This funny properties of Borwein integrals is related to the Fourier transform of Sinc function FourierTransform[Sinc[x], x, k] 1/2 Sqrt[Pi/2] (Sign[1 - k] + Sign[1 + k]) Plot[%, {k, -2, 2}, Filling -> 0] which is the box function. The result is $\pi/2$ while the sum $$ 1/3+1/5+\dots+1/n $$ B_n = \frac{\pi}{2} - \pi \bigg(\sum_{k=3,5,\ldots}^n\frac{1}{k} -1\biggr)^\frac{n-1}{2}\prod_{k=3,5,\dots}^n\frac{k}{k-1}. $$ For $n=15$ it is equal to $$ \frac{46780...

list manipulation - Selecting multiple columns from a matrix?

Sample data: data = { {{2013, 1, 1}, 24.13, 167.67, 231.82}, {{2013, 1, 2}, 32.15, 170.92, 225.99}, {{2013, 1, 3}, 35.43, 172.68, 221.67}, {{2013, 1, 4}, 36.73, 173.05, 218.32}, {{2013, 1, 5}, 58.19, 165.96, 197.05}, {{2013, 1, 6}, 69.99, 163.50, 187.52}, {{2013, 1, 7}, 71.37, 154.21, 175.58}, {{2013, 1, 8}, 72.51, 149.66, 163.25}}; I want a DateListPlot with three graphs, so for a matrix formed by columns 1 and 2, one for columns 1 and 3, and 1 for columns 1 and 4. At the moment I'm using this code: data2 = Transpose[{data[[All, 1]], data[[All, 2]]}]; data3 = Transpose[{data[[All, 1]], data[[All, 3]]}]; data4 = Transpose[{data[[All, 1]], data[[All, 4]]}]; DateListPlot[{data2, data3, data4}, Joined -> True, Filling -> {3 -> {1}}] but I have a hunch that this can be done more efficiently. I don't like the Transpose s in particular. Any ideas? edit (for extra credit) What if I need to multiply the second column by 2, which in my solution is simp...

Blog

Search This Blog