plotting - SetOptions or other approach to imposing default styling of text in a BarChart Legend?

Gustavo Delfino's answer to an earlier question showed that it is possible to use the third argument to Placed to format text in a BarChart legend as desired. For example, without this argument, the legend text in the example below would still be small and in Times, even though I have used SetOptions to style BaseStyle for BarChart, Graphics, etc.

BarChart[RandomVariate[NormalDistribution[0, 0.6], 40], 
 ChartStyle -> Join[ConstantArray[Green, {39}], {Orange}], 
 ChartLegends -> Placed[Join[ConstantArray[None, {39}], {"Preliminary estimates"}], 
   Bottom, Style[#, FontFamily -> "Arial", FontSize -> 14] &]]

enter image description here

Is there a way to set this globally? I’d like to enforce the font style of legends in a package, the way I have already done for the frame around the legend using Mr.Wizard’s answer to an earlier question of mine on StackOverflow. I would have thought some setting of BaseStyle should work but these are the only (undocumented) options that Legending`GridLegend takes:

Options[Legending`GridLegend]

{"LegendPlacementFunction" -> Automatic, 
 LegendAppearance -> Automatic, 
 Legending`LegendContainer -> Automatic, 
 Legending`LegendHeading -> None, Legending`LegendImage -> Automatic, 
 Legending`LegendImage -> Automatic, 
 Legending`LegendLayout -> Automatic, 
 Legending`LegendPosition -> Automatic, 

 Legending`LegendSize -> Automatic}

Answer

I'm not certain I understand your requirements, but if you liked my prior answer that you referenced, why not use it here too? Since the LegendContainer is applied to the legend you can use it to insert directives:

SetOptions[Legending`GridLegend, 
  Legending`LegendContainer -> (Append[#, {Red, Bold, FontFamily -> "Helvetica"}] &) ]

BarChart[{{1, 2, 3}, {1, 3, 2}, {5, 2}}, 
  ChartLegends -> {"some", "text", "here"} ]

Mathematica graphics

Comments

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.

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