Skip to main content

front end - Forcing Mathematica to recognize a symbol without defining it


In the Mathematica front-end, symbols that have been defined are colored black and symbols with no definition associated are colored blue. This is useful to prevent spelling mistakes. Also, defined symbols appear in the autocomplete (as of Mathematica v9.0).


I have a symbol chrom with no definitions associated, but I want Mathematica to recognize it. That is, I want that when I type chrom in the front end, it appears colored black, and I want it to appear in the autocomplete.


I can't associate a definition with chrom (as in chrom = ... or chrom[..] = .., because then if chrom appears in the evaluation of an expression, it will be replaced by the associated defined value. This is not the behavior I want.


In other words, is there a Mathematica function that does the opposite of Remove? Remove removes a symbol from the symbol table. How can I add a symbol to the symbol table without associating a definition with it?



Answer



Update


In a comment MB1965 proposed an undocumented but apparently canonical function to do this in recent versions. It is DeclareKnownSymbols. It takes a String or list of Strings, e.g.:


DeclareKnownSymbols[{"var", "res"}]


After this var and res are colored as known Symbols.




As far as I know the syntax highlighting for defined Symbols depends on one of the Symbol's *Values lists being non-empty. As suggested in the comments one way, and perhaps the best, is to simply assign the Symbol to itself:


symbol = symbol

OwnValues[symbol]


{HoldPattern[symbol] :> symbol}


Other rules existing in one of the *Values lists also work, even invalid ones:


Remove[symbol]

OwnValues[symbol] = {1 -> 1};

This rule will be replaced as soon as symbol is assigned:


symbol = None;

OwnValues[symbol]



{HoldPattern[symbol] :> None}

Another approach is to define a context coloring for your Symbols, and specifically create all of them in that context. First define the coloring Option and add the context to the $ContextPath:


SetOptions[$FrontEndSession, 
AutoStyleOptions -> {"SymbolContextStyles" -> {"highlight`" -> Green}}]

AppendTo[$ContextPath, "highlight`"];


Then simply list your fully-qualified Symbols to create them:


{highlight`symbol1, highlight`symbol2, highlight`symbol3};

At this point the plain Symbol names will be highlighted as specified:


enter image description here


Comments

Popular posts from this blog

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1....