Skip to main content

input forms - Explicit digit-count (precision) of real number


I'm trying to do something which seems like it should be simpler than it is (at least in my attempts at it). I have some code where I read in a list of numbers generated for me by a coworker. These numbers have varying degrees of precision, so the list might be something like


hisData = {0.05467`, 12.34230`, 4.69`, 9.3452`, ...}

I want to compare this to a list that I generated myself, where each number may have different degrees of precision. So my list might read


myData = {0.0547`, 12.34231`, 4.6877`, 9.345`, ...}


The comparison must be done in a particular way: all decimal digits that appear explicitly in any pair of numbers must agree exactly, except possibly when rounding is needed to make the number of digits match, but the number of digits given need not be the same. In the example lists above, all but the second pair of elements "agree". This would be easy enough to do if I had a function called, say, explicitPrecision, that counted the number of digits before and after the decimal that were explicitly typed by the user, so that


explicitPrecision[0.0547`] = {0, 4} (* 0 digits before the decimal, 4 after *)
explicitPrecision[12.34230`] = {2, 5} (* 2 digits before the decimal, 5 after *)

(In the later example, the trailing 0 counts as an explicit digit because it was typed before the backtick). The problem is that the built-in function that I would expect to help me accomplish this, Precision, assumes that all "short" numbers, less than around 16 digits are MachinePrecision. That may be good for numerics, but it isn't what I want to do in this case.


My current attempt uses RealDigits, but that doesn't really work since that function tacks on extra trailing zeros to the digitlist. I can also imagine a solution which manipulates the numbers as strings, but that seems hacky, and furthermore, I do want rounding to work in the appropriate cases so that, for instance, 0.05467 and 0.0547 are marked as equivalent, and that seems hard to do with strings. Also solutions using Round or Chop don't naively seem like they'd work to me since one would have to know in advance to what decimal place one wanted to round. To summarize, really what I'd like is to be able to tell Mathematica to use BigNum-like comparison operations in certain specific places rather than floating point, but I don't want to have to load any external packages. Thanks in advance for your help, and please let me know if any clarification is required.


Edit: To clarify, what is a simple way, using only built-in Mathematica functions accomplish the comparison I spoke about above, and/or to implement the explicitPrecision function I described?



Answer



Its a bit like pulling teeth, but here is a way to preserve keyed-in numbers as strings:



$PreRead = ReplaceAll[#, s_String /;
StringMatchQ[s, NumberString] :> ((Characters @@ #) &@
HoldForm[s]) ] &;
hisData = StringJoin /@ {0.05467, 12.34230, 4.69, 9.3452}
myData = StringJoin /@ {0.0547, 12.34231, 4.6877, 9.345}
$PreRead =.;


{"0.05467", "12.34230", "4.69", "9.3452"}


{"0.0547", "12.34231", "4.6877", "9.345"}




with a handful of values you may as well type in the quote marks, but this would be handy if you pasted in a table.


then for example ( with @m_goldberg's explicitprecision )


 explicitPrecision /@ hisData


{{0, 5}, {2, 5}, {1, 2}, {1, 4}}



of course when you need the actual numbers you do this:


 (ToExpression @ hisData)



{0.05467, 12.3423, 4.69, 9.3452}



-edit- a little cleaner..


 $PreRead = ReplaceAll[#, s_String /;
StringMatchQ[s, NumberString] :>
StringJoin[
Join[{"\""}, ((Characters @@ #) &@HoldForm[s]), {"\""} ]]] &;
hisData = {0.05467, 12.34230, 4.69, 9.3452}

myData = { 0.0547, 12.34231, 4.6877, 9.345}
$PreRead =.;

arbitrary precision


convert a string representation of a number to an arbitrary precision number:


 arbp[s_] := 
Module[{dp, p, pr}, If[ StringFreeQ[s, "."] , ToExpression[s],
dp = First@First@StringPosition[s, "."];
pr = StringLength[s] - dp ;
p = (StringLength[#] + 1 -

First@First@StringPosition[ # , Except["0" ]]) &@ StringDrop[ s, {dp}];
N[ Floor[ToExpression[ s] 10^pr ]/ 10^pr , p]]]
$PreRead =
ReplaceAll[#, s_String /; StringMatchQ[s, NumberString] :>
StringJoin[ Join[{"\""}, ((Characters @@ #) &@HoldForm[s]), {"\""}]]] &;
hisData = arbp /@ {0.05467, 12.34230, 4.69, 9.3452}
$PreRead =.;


{0.05467, 12.34230, 4.69, 9.3452}




 Precision /@ hisData


{4., 7., 3., 5.}



this should be carefully validated .. ( it breaks with "0.000" .. zero needs to be treated as a special case )


Comments

Popular posts from this blog

plotting - How to draw lines between specified dots on ListPlot?

I would like to create a plot where I have unconnected dots and some connected. So far, I have figured out how to draw the dots. My code is the following: ListPlot[{{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4,13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full] I have thought using ListLinePlot command, but I don't know how to specify to the command to draw only selected lines between the dots. Do have any suggestions/hints on how to do that? Thank you. Answer One possibility would be to use Epilog with Line : ListPlot[ {{1, 1}, {2, 2}, {3, 3}, {4, 4}, {1, 4}, {2, 5}, {3, 6}, {4, 7}, {1, 7}, {2, 8}, {3, 9}, {4, 10}, {1, 10}, {2, 11}, {3, 12}, {4, 13}, {2.5, 7}}, Ticks -> {{1, 2, 3, 4}, None}, AxesStyle -> Thin, TicksStyle -> Directive[Black, Bold, 12], Mesh -> Full, Epilog -> { Line[ ...

equation solving - Invert and fit implicitly defined curve

I need to fit an implicitly defined curve. I thought I could get some data out of Solve , and then using FindFit . Therefore, I would like to find the relation the parametric curve defined by $F(x,y)=0$: Solve[-(1/2) + 1/2 (0.41202 BesselK[0, 0.1 Sqrt[x^2 + y^2]] + (0.101483 x BesselK[1, 0.1 Sqrt[x^2 + y^2]])/Sqrt[x^2 + y^2]) == 0, y] But I can't get an output: Solve was unable to solve the system with inexact coefficients or the system obtained by direct rationalization of inexact numbers present in the system. Since many of the methods used by Solve require exact input, providing Solve with an exact version of the system may help. >> Edit: In particular, I would like to fit the data coming from the curve with the expression of another curve, and not with a function $f(x)$. In particular, since this clearly looks like a cardioid , I would like it to fit to something like it. What other strategies could I try?

dynamic - How can I make a clickable ArrayPlot that returns input?

I would like to create a dynamic ArrayPlot so that the rectangles, when clicked, provide the input. Can I use ArrayPlot for this? Or is there something else I should have to use? Answer ArrayPlot is much more than just a simple array like Grid : it represents a ranged 2D dataset, and its visualization can be finetuned by options like DataReversed and DataRange . These features make it quite complicated to reproduce the same layout and order with Grid . Here I offer AnnotatedArrayPlot which comes in handy when your dataset is more than just a flat 2D array. The dynamic interface allows highlighting individual cells and possibly interacting with them. AnnotatedArrayPlot works the same way as ArrayPlot and accepts the same options plus Enabled , HighlightCoordinates , HighlightStyle and HighlightElementFunction . data = {{Missing["HasSomeMoreData"], GrayLevel[ 1], {RGBColor[0, 1, 1], RGBColor[0, 0, 1], GrayLevel[1]}, RGBColor[0, 1, 0]}, {GrayLevel[0], GrayLevel...