Skip to main content

graphics - How to speed up TextJustification in Mathematica 10


Based on this question: - Version 7 print environment - I set up two 10 page test documents in version 7.0.1 and version 10.1. The version 7 document exported to PDF in 4.18 seconds whereas the version 10 export took 424.6 seconds.


Can I speed up export from version 10?


These are the test exports.


For Version 7


time = DateList[];
SetOptions[$FrontEndSession,

  PrintingOptions -> {"PrintingMargins" -> {{45, 43}, {17, 31}},
    "FirstPageHeader" -> False, "FirstPageFooter" -> False,
    "RestPagesHeader" -> False, "RestPagesFooter" -> False,
    "Magnification" -> 1}];
text = StringReplace[StringTake[
    ExampleData[{"Text", "Prufrock"}], 4221],
   FromCharacterCode[{195, 162, 128, 194, 153}] -> "'"];
square = Graphics[{Orange, Rectangle[{0, 0}, {70, 70}]},
   PlotRange -> {{0, 70}, {0, 70}}];
column = Table[Inset[square, {415, 100 i}, {Left, Bottom},

    {70, 70}], {i, 0, 9}];
page = Graphics[{White, Rectangle[{0, 0}, {500, 973}], Black,
    Inset[TextCell[text, LineSpacing -> {0, 16},
      TextJustification -> 1], {0, 973}, {Left, Top}, {400, 973}],
    column}, PlotRange -> {{0, 500}, {0, 973}}, ImageSize -> 500, 
   BaseStyle -> {FontFamily -> "Times", FontWeight -> "Plain", FontSize -> 14}];
nb = CreateDocument[ConstantArray[ExpressionCell[page, "Print"], 10],
   WindowSize -> 800];
filename = StringJoin["v", ToString[Round@$VersionNumber], ".pdf"];
Quiet@DeleteFile[filename];

Export[filename, nb];
NotebookClose[nb];
DateDifference[time, DateList[], "Second"]


{4.18004, Second}



For Version 10


time = DateList[];
SetOptions[$FrontEndSession,

  PrintingOptions -> {"PrintingMargins" -> {{11, 43}, {15, 31}},
    "FirstPageHeader" -> False, "FirstPageFooter" -> False,
    "RestPagesHeader" -> False, "RestPagesFooter" -> False,
    "Magnification" -> 1}];
text = StringReplace[StringTake[
    ExampleData[{"Text", "Prufrock"}], 4221],
   FromCharacterCode[{195, 162, 128, 194, 153}] -> "'"];
square = Graphics[{Orange, Rectangle[{0, 0}, {70, 70}]},
   PlotRange -> {{0, 70}, {0, 70}}];
column = Table[Inset[square, {415, 100 i}, {Left, Bottom},

    {70, 70}], {i, 0, 9}];
page = Graphics[{White, Rectangle[{0, 0}, {500, 973}], Black,
    Inset[TextCell[text, LineSpacing -> {0, 17},
      TextJustification -> 1], {0, 973}, {Left, Top}, {400, 973}],
    column}, PlotRange -> {{0, 500}, {0, 973}}, ImageSize -> 555,
   BaseStyle -> {FontFamily -> "Times", FontWeight -> "Plain", FontSize -> 15.5}];
nb = CreateDocument[ConstantArray[ExpressionCell[page, "Print"], 10],
   WindowSize -> 800];
filename = StringJoin["v", ToString[Round@$VersionNumber], ".pdf"];
Quiet@DeleteFile[filename];

Export[filename, nb];
NotebookClose[nb];
DateDifference[time, DateList[], "Second"]


424.599 s





Comments

Post a Comment

Popular posts from this blog

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...
Post a Comment
Read more

mathematical optimization - Minimizing using indices, error: Part::pkspec1: The expression cannot be used as a part specification

I want to use Minimize where the variables to minimize are indices pointing into an array. Here a MWE that hopefully shows what my problem is. vars = u@# & /@ Range[3]; cons = Flatten@ { Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; Minimize[{Total@((vec1[[#]] - vec2[[u[#]]])^2 & /@ Range[1, 3]), cons}, vars, Integers] The error I get: Part::pkspec1: The expression u[1] cannot be used as a part specification. >> Answer Ok, it seems that one can get around Mathematica trying to evaluate vec2[[u[1]]] too early by using the function Indexed[vec2,u[1]] . The working MWE would then look like the following: vars = u@# & /@ Range[3]; cons = Flatten@{ Table[(u[j] != #) & /@ vars[[j + 1 ;; -1]], {j, 1, 3 - 1}], 1 vec1 = {1, 2, 3}; vec2 = {1, 2, 3}; NMinimize[ {Total@((vec1[[#]] - Indexed[vec2, u[#]])^2 & /@ R...
Post a Comment
Read more

What is and isn't a valid variable specification for Manipulate?

I have an expression whose terms have arguments (representing subscripts), like this: myExpr = A[0] + V[1,T] I would like to put it inside a Manipulate to see its value as I move around the parameters. (The goal is eventually to plot it wrt one of the variables inside.) However, Mathematica complains when I set V[1,T] as a manipulated variable: Manipulate[Evaluate[myExpr], {A[0], 0, 1}, {V[1, T], 0, 1}] (*Manipulate::vsform: Manipulate argument {V[1,T],0,1} does not have the correct form for a variable specification. >> *) As a workaround, if I get rid of the symbol T inside the argument, it works fine: Manipulate[ Evaluate[myExpr /. T -> 15], {A[0], 0, 1}, {V[1, 15], 0, 1}] Why this behavior? Can anyone point me to the documentation that says what counts as a valid variable? And is there a way to get Manpiulate to accept an expression with a symbolic argument as a variable? Investigations I've done so far: I tried using variableQ from this answer , but it says V[1...
Post a Comment
Read more