Skip to main content

plotting - How to plot paired smooth histogram/distribution plots?



I've been trying to get paired distribution (aka "violin") plots like those shown below for a few hours, but all my attempts have failed.


enter image description here


The key features here are



  1. paired smooth histograms/distribution plots with a common vertical abscissa and divergent horizontal ordinates;

  2. different fill colors for the two subplots;


The closest Mathematica has are DistributionCharts, but these plots are not paired (i.e. they are always symmetrical).




I first tried SmoothHistogram, but it appears that there's no simple way to get a SmoothHistogram with a vertical abscissa.



Next I tried PairedSmoothHistogram, but I can't manage to assign different fill colors to the two sides.


BlockRandom[SeedRandom[0];
Quiet[
PairedSmoothHistogram[
RandomVariate[NormalDistribution[], 100]
, RandomVariate[NormalDistribution[], 100]
, AspectRatio -> Automatic
, Axes -> {False, True}
, Ticks -> None
, Spacings -> 0

, ImageSize -> 30
, Filling -> Axis
]
, OptionValue::nodef
]
]


Mathematica graphics




Then I tried a combination of SmoothKernelDistribution and either ListPlot, ParametricPlot or ContourPlot, but this won't work because neither ParametricPlot nor ContourPlot accepts a Fill option, and I can't figure out how to get ListPlot to fill the spaces between the curves and the vertical axis.


For example,


violin[data1_, data2_, rest___] := Module[
{ d1 = SmoothKernelDistribution[data1]
, d2 = SmoothKernelDistribution[data2]
, x
, xrange
}, xrange = {x, Sequence @@ (#[data1, data2] & /@ {Min, Max})}
; ParametricPlot[ {{-PDF[d1, x], x}, {PDF[d2, x], x}}
, Evaluate@xrange

, rest
, PlotRange -> All
, Axes -> {None, True}
, Ticks -> None
, PlotRangePadding -> {Automatic, None}
]
];

BlockRandom[SeedRandom[0];
violin[RandomVariate[NormalDistribution[], 100],

RandomVariate[NormalDistribution[], 100],
ImageSize -> 30
]
]


Mathematica graphics





I didn't expect this would be so hard. My brain is now fried.



Does anyone know how one does this?



Answer



Here is something using a custom ChartElementFunction


Module[{c = 0},
half[{{xmin_, xmax_}, {ymin_, ymax_}}, data_, metadata_] := (c++;
Map[Reverse[({0, Mean[{xmin, xmax}]} + # {1, (-1)^c})] &,
First@Cases[
First@Cases[InputForm[SmoothHistogram[data, Filling -> Axis]],
gc_GraphicsComplex :> Normal[gc], ∞],
p_Polygon, ∞], {2}])]


(thanks to @halirutan for reminding me about how to do closures in WL).


data = RandomVariate[NormalDistribution[0, 1], {4, 2, 100}];

DistributionChart[data, BarSpacing -> -1, ChartElementFunction -> half]

Mathematica graphics


Comments

Popular posts from this blog

plotting - Filling between two spheres in SphericalPlot3D

Manipulate[ SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, Mesh -> None, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], {n, 0, 1}] I cant' seem to be able to make a filling between two spheres. I've already tried the obvious Filling -> {1 -> {2}} but Mathematica doesn't seem to like that option. Is there any easy way around this or ... Answer There is no built-in filling in SphericalPlot3D . One option is to use ParametricPlot3D to draw the surfaces between the two shells: Manipulate[ Show[SphericalPlot3D[{1, 2 - n}, {θ, 0, Pi}, {ϕ, 0, 1.5 Pi}, PlotPoints -> 15, PlotRange -> {-2.2, 2.2}], ParametricPlot3D[{ r {Sin[t] Cos[1.5 Pi], Sin[t] Sin[1.5 Pi], Cos[t]}, r {Sin[t] Cos[0 Pi], Sin[t] Sin[0 Pi], Cos[t]}}, {r, 1, 2 - n}, {t, 0, Pi}, PlotStyle -> Yellow, Mesh -> {2, 15}]], {n, 0, 1}]

plotting - Plot 4D data with color as 4th dimension

I have a list of 4D data (x position, y position, amplitude, wavelength). I want to plot x, y, and amplitude on a 3D plot and have the color of the points correspond to the wavelength. I have seen many examples using functions to define color but my wavelength cannot be expressed by an analytic function. Is there a simple way to do this? Answer Here a another possible way to visualize 4D data: data = Flatten[Table[{x, y, x^2 + y^2, Sin[x - y]}, {x, -Pi, Pi,Pi/10}, {y,-Pi,Pi, Pi/10}], 1]; You can use the function Point along with VertexColors . Now the points are places using the first three elements and the color is determined by the fourth. In this case I used Hue, but you can use whatever you prefer. Graphics3D[ Point[data[[All, 1 ;; 3]], VertexColors -> Hue /@ data[[All, 4]]], Axes -> True, BoxRatios -> {1, 1, 1/GoldenRatio}]

plotting - Mathematica: 3D plot based on combined 2D graphs

I have several sigmoidal fits to 3 different datasets, with mean fit predictions plus the 95% confidence limits (not symmetrical around the mean) and the actual data. I would now like to show these different 2D plots projected in 3D as in but then using proper perspective. In the link here they give some solutions to combine the plots using isometric perspective, but I would like to use proper 3 point perspective. Any thoughts? Also any way to show the mean points per time point for each series plus or minus the standard error on the mean would be cool too, either using points+vertical bars, or using spheres plus tubes. Below are some test data and the fit function I am using. Note that I am working on a logit(proportion) scale and that the final vertical scale is Log10(percentage). (* some test data *) data = Table[Null, {i, 4}]; data[[1]] = {{1, -5.8}, {2, -5.4}, {3, -0.8}, {4, -0.2}, {5, 4.6}, {1, -6.4}, {2, -5.6}, {3, -0.7}, {4, 0.04}, {5, 1.0}, {1, -6.8}, {2, -4.7}, {3, -1.