Skip to main content

function construction - Clean and handy Options management/filtering


the case


I want to be able to create a function with some default options but also without need to add full explicit list of options available for it.


And then inside I want to be able to filter from given and default options, those which are Button options or Tooltip options for example.


So something like:


Options[f] = {(*list of default options*)}


f[args__, OptionsPattern[]]:=Column[{
(*Options that are suitable for Button*),
(*Options that are suitable for Tooltip*),
OptionValue[(*specific name*)]
}]

And I wasn't able to get this with built in Options management functions: OptionsPattern[], OptionValue, FilterRules etc.


additional requirements





  1. I want to avoid Options[f] = Join[customOptions, Options[Button], ...].


    I don't think is a good solution, there may be duplicates in customOptions for them and an explicit list of Options[f] grows.




  2. I want to be able to provide any option to the function without error messsage e.g.: Unknown option Apparance for f...




  3. We can get 2. by skipping OptionsPattern[] in definition but without it we can't use built in OptionValue. I want to be able to refer to functions by their names.





  4. Rules filtering mechanism should not produce duplicates. I know Button[..., ImageSize->300, ImageSize->200] will behave stable but I find it ugly.




my approach


(* auxiliary functions *)

mergeRules = GatherBy[Join[##], First][[All, 1]] &;

optionValue = #2 /. # &;


(* function definition *)

ClearAll[f];
Options[f] = {"Test" -> 1, ImageSize -> 100, TooltipDelay -> 20};

f[x_, optionsPattern : (_Rule | _RuleDelayed) ...] := With[{
opt = mergeRules[{optionsPattern}, Options[f]]}
,
Column@{
FilterRules[opt, Options@Button],

FilterRules[opt, Options@Tooltip],
optionValue[opt, "Test"]
}
]

So I need to start my definitions with With[{ opt = mergeRules[ {optionsPattern}, Options[f]]}, which does not seem to be a big problem, but why I have to do this?


tests


f[1, Appearance -> "Palette"]



{Appearance->Palette, ImageSize->100} 
{TooltipDelay->20}
1

f[1, ImageSize -> 200]


{ImageSize->200}
{TooltipDelay->20}
1


f[1]


{ImageSize->100}
{TooltipDelay->20}
1

question


Is there simpler approach, with built functions maybe? Or should I include Options[Button] etc. to Options[f] and count on the fact that when given duplicates, first one wins?



Edits


Mr.Wizard's answer fulfills points:


1 automatically, 2/3 by using OptionsPattern[{f,Button, ...}]. So still 4 needs custom filtering function but it is a good answer anyway.




Comments

Popular posts from this blog

front end - keyboard shortcut to invoke Insert new matrix

I frequently need to type in some matrices, and the menu command Insert > Table/Matrix > New... allows matrices with lines drawn between columns and rows, which is very helpful. I would like to make a keyboard shortcut for it, but cannot find the relevant frontend token command (4209405) for it. Since the FullForm[] and InputForm[] of matrices with lines drawn between rows and columns is the same as those without lines, it's hard to do this via 3rd party system-wide text expanders (e.g. autohotkey or atext on mac). How does one assign a keyboard shortcut for the menu item Insert > Table/Matrix > New... , preferably using only mathematica? Thanks! Answer In the MenuSetup.tr (for linux located in the $InstallationDirectory/SystemFiles/FrontEnd/TextResources/X/ directory), I changed the line MenuItem["&New...", "CreateGridBoxDialog"] to read MenuItem["&New...", "CreateGridBoxDialog", MenuKey["m", Modifiers-...

How to thread a list

I have data in format data = {{a1, a2}, {b1, b2}, {c1, c2}, {d1, d2}} Tableform: I want to thread it to : tdata = {{{a1, b1}, {a2, b2}}, {{a1, c1}, {a2, c2}}, {{a1, d1}, {a2, d2}}} Tableform: And I would like to do better then pseudofunction[n_] := Transpose[{data2[[1]], data2[[n]]}]; SetAttributes[pseudofunction, Listable]; Range[2, 4] // pseudofunction Here is my benchmark data, where data3 is normal sample of real data. data3 = Drop[ExcelWorkBook[[Column1 ;; Column4]], None, 1]; data2 = {a #, b #, c #, d #} & /@ Range[1, 10^5]; data = RandomReal[{0, 1}, {10^6, 4}]; Here is my benchmark code kptnw[list_] := Transpose[{Table[First@#, {Length@# - 1}], Rest@#}, {3, 1, 2}] &@list kptnw2[list_] := Transpose[{ConstantArray[First@#, Length@# - 1], Rest@#}, {3, 1, 2}] &@list OleksandrR[list_] := Flatten[Outer[List, List@First[list], Rest[list], 1], {{2}, {1, 4}}] paradox2[list_] := Partition[Riffle[list[[1]], #], 2] & /@ Drop[list, 1] RM[list_] := FoldList[Transpose[{First@li...

functions - Get leading series expansion term?

Given a function f[x] , I would like to have a function leadingSeries that returns just the leading term in the series around x=0 . For example: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x)] x and leadingSeries[(1/x + 2 + (1 - 1/x^3)/4)/(4 + x)] -(1/(16 x^3)) Is there such a function in Mathematica? Or maybe one can implement it efficiently? EDIT I finally went with the following implementation, based on Carl Woll 's answer: lds[ex_,x_]:=( (ex/.x->(x+O[x]^2))/.SeriesData[U_,Z_,L_List,Mi_,Ma_,De_]:>SeriesData[U,Z,{L[[1]]},Mi,Mi+1,De]//Quiet//Normal) The advantage is, that this one also properly works with functions whose leading term is a constant: lds[Exp[x],x] 1 Answer Update 1 Updated to eliminate SeriesData and to not return additional terms Perhaps you could use: leadingSeries[expr_, x_] := Normal[expr /. x->(x+O[x]^2) /. a_List :> Take[a, 1]] Then for your examples: leadingSeries[(1/x + 2)/(4 + 1/x^2 + x), x] leadingSeries[Exp[x], x] leadingSeries[(1/x + 2 + (1 - 1/x...